Subject:
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Re: math question (or pattern... whatever...)
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Newsgroups:
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lugnet.off-topic.geek
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Date:
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Tue, 4 Mar 2003 22:12:07 GMT
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Viewed:
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464 times
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In lugnet.off-topic.geek, James Brown writes:
> No, because you only tried to remove r2. We are only removing *a* red ball
> from the bag; because there are 2 red balls, and only 1 is ever in our hand,
> there is always a red ball in the bag to remove. It is irrelevant whether
> that ball is r1 or r2.
>
> Redoing it with numbers:
>
> hand bag
> r1 r2 w
> r2 r1 w
> w r1 r2
>
> Now removing a red ball from the bag we get:
>
> hand bag
> r1 w (r2 is the only red ball, it is removed)
> r2 w (r2 is the only red ball, it is removed)
Bleargh! typo.
r2 w (r1 is the only red ball, it is removed)
> w r1 OR r2 (either may be removed, as both are in the bag)
>
> James
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Message has 2 Replies:
 | | Re: math question (or pattern... whatever...)
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| (...) Saw that ;) but understood... but if we're talking one instance--one event--and that's what we're, indeed, talking about--you are on a game show, one event--you have one chance of winning one car behind one door.... so you have 3 doors I won't (...) (22 years ago, 5-Mar-03, to lugnet.off-topic.geek)
| | | Re: math question (or pattern... whatever...)
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| (...) Saw that ;) but understood... but if we're talking one instance--one event--and that's what we're, indeed, talking about--you are on a game show, one event--you have one chance of winning one car behind one door.... so you have 3 doors I won't (...) (22 years ago, 5-Mar-03, to lugnet.off-topic.geek)
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Message is in Reply To:
| | Re: math question (or pattern... whatever...)
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| (...) Why not? There are two different red balls, so each of those red balls is equally likely as the white ball to be in my hand. (...) No, because you only tried to remove r2. We are only removing *a* red ball from the bag; because there are 2 red (...) (22 years ago, 4-Mar-03, to lugnet.off-topic.geek)
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