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Subject: 
Re: math question (or pattern... whatever...)
Newsgroups: 
lugnet.off-topic.geek
Date: 
Tue, 4 Mar 2003 20:38:13 GMT
Viewed: 
378 times
  
In lugnet.off-topic.geek, David Eaton writes:
In lugnet.off-topic.geek, David Koudys writes:
In lugnet.off-topic.geek, David Eaton writes:
You see, you now have 2 listings for "Choose 1, Prize 1", "Coose 2, Prize
2", and "Choose 3, Prize 3", when each deserves *equal* probability to each
other possibility, like "Choose 2, Prize 3"-- which in your list, only gets
one entry. Basically, if you want to count "Choose 1, Prize 1, Door Revealed
2" and "Choose 1, Prize 1, Door Revealed 3" as *different*, then you have to
count each *other* selection twice as well, resulting in:

That doesn't make sense at all--

If I choose door 1 and the prize is behind door 1, the host can choose to
show me door 2 *or* door 3 - 2 possibilities

If I choose door one and the prize is behind door 2, the host can *only*
show me door 3 - one possibility

If I choose door one and the prize is behind door 3, the host can *only*
show me door 2 - one possibility

So if I choose door 1, there are only 4 possibilities, not 6, as you listed
below.

Now whether I switch or stay, as listed above, is 50/50

Doh. This is just coming back to haunt me. I should never have included the
"door revealed" column. It's entirely irrelevant, and is only serving to
confuse. A better list:

Prize   Choice   Switch or Stay?
1       1        stay!
1       2        switch!
1       3        switch!
2       1        switch!
2       2        stay!
2       3        switch!
3       1        switch!
3       2        switch!
3       3        stay!


If I were to think about it like a sequence of events, logically leading up
to the end choice, it would go something like this--

The event starts--

Contestant picks a door -- 1, 2, or 3

If this is all there is to the contest, we have 33 percent chance of picking
the right door, as posted above (listed here for clarity)

Door    Prize    Win/Lose
1       1        win!
1       2        lose!
1       3        lose!
2       1        lose!
2       2        win!
2       3        lose!
3       1        lose!
3       2        lose!
3       3        win!

3 wins, 6 losses--33 percent

But this isn't where we put the stake in the ground...

The event continues--

One door, which isn't my picked door or the prize door, is revealed,
hypothetically, let's say door number 3

So anything with a 3 in it cannot be a choice, for it is eliminated--

Door    Prize    Win/Lose
1       1        win!
1       2        lose!
1       3        lose! *delete me*
2       1        lose!
2       2        win!
2       3        lose! *delete me*
3       1        lose! *delete me*
3       2        lose! *delete me*
3       3        win! *delete me*

Leaving--

Door    Prize    Win/Lose
1       1        win!
1       2        lose!
2       1        lose!
2       2        win!

So here's the stake in the ground--the end of the event--I must choose
between 2 doors--the one I originally wanted, or the other door remaining...

And, it's 50/50...

k, now I'm just more confus-ed... :)

Dave K

Effectively, there's a 1/3 chance that the prize is in door #1. And there's
a 1/9 chance that you *PICK* door number 1 AND that the prize is back there.
Further, there's a 1/18 chance that it's Prize 1, Choice 1, door revealed 2,
and another 1/18 chance that it's Prize 1, Choice 2, door revealed 3.

HOWEVER. It's a 1/3 chance that the prize is in door #1. 1/9 chance that you
pick door #2. And since there's only ONE choice of doors to be revealed,
it's a 1/9 chance that it's Prize 1, Choice 2, door revealed 3.

Hence, probability wise (using Bruce's model):

Prob.  Choose  Prize  Door Revealed   Possible choices
1/18     1       1        2           Stay (win). Switch (lose).
1/18     1       1        3           Stay (win). Switch (lose).
1/9      1       2        3           Stay (lose).  Switch (win).
1/9      1       3        2           Stay (lose).  Switch (win).

Prob.  Choose  Prize  Door Revealed   Possible choices
1/18     2       2        1           Stay (win). Switch (lose).
1/18     2       2        3           Stay (win). Switch (lose).
1/9      2       1        3           Stay (lose).  Switch (win).
1/9      2       3        1           Stay (lose).  Switch (win).

Prob.  Choose  Prize  Door Revealed   Possible choices
1/18     3       3        1           Stay (win). Switch (lose).
1/18     3       3        2           Stay (win). Switch (lose).
1/9      3       1        2           Stay (lose).  Switch (win).
1/9      3       2        1           Stay (lose).  Switch (win).

DaveE

Dave K



Message is in Reply To:
  Re: math question (or pattern... whatever...)
 
(...) Doh. This is just coming back to haunt me. I should never have included the "door revealed" column. It's entirely irrelevant, and is only serving to confuse. A better list: Prize Choice Switch or Stay? 1 1 stay! 1 2 switch! 1 3 switch! 2 1 (...) (22 years ago, 4-Mar-03, to lugnet.off-topic.geek)

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