Subject:
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Re: math question (or pattern... whatever...)
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Newsgroups:
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lugnet.off-topic.geek
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Date:
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Mon, 3 Mar 2003 22:01:45 GMT
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Viewed:
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253 times
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In lugnet.off-topic.geek, David Koudys writes:
> My friend calculated it this way
>
> r(1) r(2) b w
>
> the 'event' is that you have 2 balls in your hand, one of which is red
>
> so out of all the possible unique combinations (6)--
>
> r(1) r(2)
> r(1) b
> r(1) w
> r(2) b
> r(2) w
> b w
Yep, you're right, your friend is wrong. The problem is that you *wouldn't*
count "r(2) r(1)" if order didn't matter. But then again, the thing he's
forgetting is that if you don't count "r(2) r(1)", then you also CAN'T count
*both* "r(1) b" and "r(2) b".
Now, here's a trickier one:
Ever watched the old game show "Let's Make a Deal"? Sometimes, they'd offer
people things similar to this scenario. You're a game show contestant. Bob
the host shows you 3 doors. You win whatever's behind the door you pick.
Behind 2 of the doors are goats. Behind the other door, there's a brand new
sports car.
You pick door X. Now, before Bob shows you what's behind door X, he opens up
door Y, and shows you... a goat! Bob now says you have a chance to change
your mind, and instead of picking door X, you can switch to door Z.
What's the probability that the sports car is behind door Z versus door X?
DaveE
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Message has 1 Reply:
Message is in Reply To:
 | | math question (or pattern... whatever...)
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| k, here's something that came across my desk... you have a bag with 4 marbles in it. 2 of the marbles are red 1 marble is white 1 marble is blue you reach in and grab 2 random marbles you open up your hand a bit to only see the colour of one of (...) (22 years ago, 3-Mar-03, to lugnet.off-topic.geek)
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