Subject:
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Re: Where's all that gravity coming from?
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Newsgroups:
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lugnet.space
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Date:
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Fri, 9 Mar 2001 00:28:36 GMT
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Viewed:
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578 times
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In lugnet.space, Erik Olson writes:
> My figures (hasn't this been done in off-topic already?)
We talked about a similar trip to Mars awhile ago (it was 40 hours, I think).
> note: 3e8 is 3 * 10^8 or 300,000,000
>
> Proxima Centauri - about 9 ly away
Actually, Proxima is 4.22. But we'd be more interested in Alpha Centauri A
and B, which are 4.35 ly distant.
> 1 year = 31557600 seconds, or 3e7 s
> c = 3e8 m/s (speed of light)
> 1 ly = 3e7 s * c
> d = Proxima Centauri = about 1e17 m
d(A&B) = 4.35 ly = 4e16 m
> Simple acceleration:
> a = 10 m/s/s (about 1g)
> d = 0.5 a t^2
> 1e17 m = 0.5 * 10 m/s/s * t^2
> Solve for 1/2 the distance (half trip)
> t = sqrt( 1e16 ) = 3e8
sqrt(4e16 / 5) = t = 8e7 s
or about 3 years for halfway, 6 for the total trip.
Steve
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Message is in Reply To:
 | | Re: Where's all that gravity coming from?
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| (...) My figures (hasn't this been done in off-topic already?) note: 3e8 is 3 * 10^8 or 300,000,000 Proxima Centauri - about 9 ly away 1 year = 31557600 seconds, or 3e7 s c = 3e8 m/s (speed of light) 1 ly = 3e7 s * c d = Proxima Centauri = about (...) (24 years ago, 8-Mar-01, to lugnet.space)
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