| |
Hi.
|
| Let's see what I can remember.
|
|> > On Tue, Nov 07, 2000 at 08:41:38PM +0000, Jude Beaudin wrote:
|> > > Let me rephrase the question:
|> > > If a man travels on a ship away from earth for 5 light years at .5c,
|> > > then returns to earth at .5c, who will have aged 20 years, the occupant
|> > > or his twin who stayed on earth?
|
| The thing to remember is that a 'light year' is a unit of
| Distance NOT one of Time. So the theory goes that he would
| experience the passage of 10 years while leaving and another
| 10 years on the return. In otherwords it takes 10 years at
| 1/2 the speed to go the same distance that light could go
| in 5 years.
|
| So I believe his body would be 20 years older on his return.
|
| The real question is: 'How much time would have passed from
| the earths point of view while he was gone?'
|
| That's one I' can't remember how to figure out. I think the
| theory is that the earth will have experienced the passage
| of a lot more time.
|
| Though a friend of mind seems to think it has less to do
| with how fast you go, and more to do with how quickly you
| accelerate to the speed you end up traveling...
|
| I'm confused now.
|
|
| -Kyle
|
|
|
Message has 1 Reply:
 | | Re: Relativity Question
|
| (...) Using this formula someone else posted: T = t/(sqrt(1-(v/C)^2)) The amount of time experienced by the twin that stays behind would be 26.67 Years. This sounds right. The longer he was gone, and/or the closer to the speed of light (C) that he (...) (24 years ago, 7-Nov-00, to lugnet.off-topic.geek, lugnet.space)
|
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