Subject:
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Re: Relativity Question
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Newsgroups:
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lugnet.off-topic.geek
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Date:
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Wed, 8 Nov 2000 20:36:32 GMT
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Viewed:
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551 times
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In lugnet.off-topic.geek, Jay Jacinto writes:
> For example: an observer accelerating away from a stationary observer would
> experience the sensation of acceleration. Conversely, the stationary observer
> would experience a gravitational field generated by the Universe accelerating
> from the other observer. So neither could determine which is in the
> accelerated inertia frame. Thus, all motion including acceleration is
> relative.
Well, thanks for throwing a monkey wrench into it for me. How do the
famous de-synchronized clocks fit into this? Obviously one of them slowed
down relative to the other. Do we infer that the ground-based clock
decelerated sufficiently to speed up time's local passage? I thought I had
a handle on this, but now I see I'm missing something.
> Also the doppler shift measured by each observer will be the same, all
> acceleration does is add an additional term as determined by the Lorentz
> transformation.
Hmm. This is the part that always messes me up. So if there is a distant
star whose light we see as red-shifted, and X is standing on Earth, while Y
takes off at .9c toward the distant star, will both X and Y perceive the
same red-shift?
Dave!
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Message has 1 Reply:
 | | Re: Relativity Question
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| (...) observer (...) Acceleration is bad ju-ju, since it isn't accounted for in special relativity. It's only in General Relativity that we get gravity thrown into the mix, and that's taught in grad school. However, from a strictly special (...) (24 years ago, 8-Nov-00, to lugnet.off-topic.geek)
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Message is in Reply To:
| | Re: Relativity Question
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| (...) However, some are moving in a certain way as to make it indistuigishable as to who is moving. i.e. me moving away from the universe is equivalent to universe moving away from me. (...) The equations are equivalent no matter what inertia frame (...) (24 years ago, 8-Nov-00, to lugnet.off-topic.geek)
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