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Subject: 
Re: Here's looking at Euclid
Newsgroups: 
lugnet.off-topic.geek
Date: 
Wed, 2 Aug 2000 19:06:51 GMT
Viewed: 
265 times
  
In lugnet.off-topic.geek, Dave Schuler writes:
In lugnet.off-topic.geek, David Eaton writes:
In lugnet.off-topic.geek, Dave Schuler writes:
In lugnet.off-topic.geek, John Gramley writes:

**snip of some rather helpful stuff**

How about this:

Suppose the two points are vertices of an inscribed octagon whose sides are
each of length X.  Would that help?

    Dave!

Well... yes, I guess... assuming you knew X, though, you could easily
calculate the diameter of the circle even without knowing the distance apart
the two points were... Then the diameter of the circle would simply be:
sqrt((((2X)/sqrt(2))+X)^2+X^2)

But if you don't know how long X is, no help (sorry)

I have the coordinates of the points, so am I correct in thinking I can
calculate X?

Nope... again, not unless you know something else (like how many verticies
there are in between the two points). You could probably come up with a good
guestimate, though, since there would only be 4 possible values for X, all of
which you could calculate (there could be either 0,1,2,or 3 verticies of the
inscribed octagon in between the two points). Then you could concievably find
the answer that appears to match most closely-- but that assumes you have can
even make a good guess...

DaveE



Message has 1 Reply:
  Re: Here's looking at Euclid
 
(...) D'oh! I should have specified that the two points are vertices of a single side of the octagon; I'm sure of that much! Am I on the right track here? Assuming that the side of the inscribed octagon is 10 units long, I'm calculating the (...) (24 years ago, 2-Aug-00, to lugnet.off-topic.geek)

Message is in Reply To:
  Re: Here's looking at Euclid
 
(...) I have the coordinates of the points, so am I correct in thinking I can calculate X? In any case, thanks to everyone for the help; I have what I need to figure it out! Dave! (24 years ago, 2-Aug-00, to lugnet.off-topic.geek)

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