Subject:
|
Re: icosahedron in soccer-ball style
|
Newsgroups:
|
lugnet.build.sculpture
|
Date:
|
Tue, 16 Sep 2003 20:54:34 GMT
|
Viewed:
|
1083 times
|
| |
|
|
In lugnet.build.sculpture, John Gerlach wrote:
>
> Now you've got me confused - how would you have a black triangle of 4/3/4?
> One '4' would be attached to the white hexagon, then what?
>
> John confused... :-)
Hoo, boy. How to explain without pictures? Hmmm... okay here goes...
Suppose the following represented two black triangles set side by side, touching
at one vertices...
_ _
\/ \/
The sides represented by "_" are 1x4's connecting to white 1x4's as per your
original construction.
The sides represented by "\" are 1x4's. When measured from the touching vertice
(sp?), the 1x1 mod.plates with side loops are at positions 2 and 4.
The sides represented by "/" are 1x3's. When measured from the touching vertice
(sp?), the 1x1 mod.plates with side loops are at positions 1 and 3.
Thus the side loop plates are still staggered for insertion of the 4L bar.
Well, that's my best shot at an explanation. Most definitely you will need to
have the black triangles one plate deeper to accomodate the 1x4 hinge plates.
Maybe I'll need to dig through my collection to see if I have enough parts to
simulate what I'm imagining and post pictures. Let me know if that would help.
Thanks for not dismissing my idea out of hand.
Alan (who didn't realize he was using FTX codes the first time he typed in the
side representations).
|
|
Message has 1 Reply:
 | | Re: icosahedron in soccer-ball style
|
| Ok, now I understand what you're going for. Interesting idea! And I can imagine why you refered to it as a "pinwheel"... :-) I was stuck on using the equalateral triangles due to me having a large collection of (URL) Polydron> (gasp! A different (...) (21 years ago, 16-Sep-03, to lugnet.build.sculpture, FTX)
|
Message is in Reply To:
| | Re: icosahedron in soccer-ball style
|
| (...) I changed it, because I was thinking you meant that each of the black triangles would have one side of length 4 (that connects to the white hexagon), and two sides of length 3 (that connect to the two ajoining black triangles within the (...) (21 years ago, 16-Sep-03, to lugnet.build.sculpture, FTX)
|
15 Messages in This Thread:
 
  
- Entire Thread on One Page:
- Nested:
All | Brief | Compact | Dots
Linear:
All | Brief | Compact
This Message and its Replies on One Page:
- Nested:
All | Brief | Compact | Dots
Linear:
All | Brief | Compact
|
|
|
|
