Subject:
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Re: threads - bug in the firmware?
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Newsgroups:
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lugnet.robotics.rcx.legos
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Date:
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Fri, 18 Jan 2002 10:11:14 GMT
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Viewed:
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1745 times
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On Thu, 17 Jan 2002, Michael Obenland wrote:
> pid1 = execi (&bumper_task, 0, NULL, PRIO_NORMAL+4, DEFAULT_STACK_SIZE);
> pid2 = execi (&left_task, 0, NULL, PRIO_NORMAL+2, DEFAULT_STACK_SIZE);
> pid3 = execi (&right_task, 0, NULL, PRIO_NORMAL, DEFAULT_STACK_SIZE);
> while( 1 ); // <<<<<<<<<<<<< this is crucial!
I would strongly suggest changing this to while(1) msleep(bignumber);.
Otherwise you're hogging the processor doing nothing important, which
could do bad things to any compute-intensive tasks you may have going.
It'll also use slightly less battery power this way since the OS would
probably be able to sleep the processor here and there. Not that this is a
large effect.
--
"From now on, we live in a world where man has walked on the moon.
And it's not a miracle, we just decided to go." -- Jim Lovell
Mike Ash - <http://www.mikeash.com/>, <mailto:mail@mikeash.com>
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Message has 1 Reply:
 | | More on threads
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| (...) Of course you are right. I think it is a bad programming style not to give your program the ability to terminate but to run in an endless loop. But what is the penalty for this bad style? I've done some investigations and here are the results: (...) (22 years ago, 18-Jan-02, to lugnet.robotics.rcx.legos)
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Message is in Reply To:
| | Re: threads - bug in the firmware?
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| Hi Mike, your problem is not because of an error in legOS. But what you do is that you start your subroutines and then you leave main()! Leaving main means that all your allocated memory is freed. The following will do the job: ---...--- cut here (...) (22 years ago, 17-Jan-02, to lugnet.robotics.rcx.legos)
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