 | | Re: See what you find when you go snooping around...
|
|
(...) Killed in the SPIKE room, and I'm trying to find a web page that will teach me how to solve for those dumb mike is twice as old as ben, ben is gay but is 4 times younger than mary, mary is high, but in really 12 times mike. I hate those. I (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| |
| | Re: See what you find when you go snooping around...
|
|
(...) Yep, that always gets me too. (...) Set it up with something you think is close, then when it doesn't work out change your estimate so the end result is closer. Example, I set two of the minifig's ages and then figured the third from that. It (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| |
| | Re: See what you find when you go snooping around...
|
|
(...) Isn't that known as algebra? How do you express gayness or highness in variables or linear systems? (I'm now going to remove that line on the rtlToronto presentation file that says "Problem solving oriented". Shameful.) Calum (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| |
| | Re: See what you find when you go snooping around...
|
|
(...) huh? algebra? is that like fake numbers and all that phooey? hummm. let me do some search on line for... how do you say.... algebra. I mean any word with bra in it has to be cool right? (...) I use variables like X, Y & Z. in fact all my (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| |
| | Re: See what you find when you go snooping around...
|
|
In lugnet.org.ca.rtltoronto, Chris Magno wrote: <snip> (...) rtlToronto's problem solving--get yer 'bot to do this! No problem Algebra's not a problem, it's hell. ;) But I always seem to work 'em out. So far, have gotten thru most of the building at (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| |
| | Re: See what you find when you go snooping around...
|
|
In lugnet.org.ca.rtltoronto, David Koudys wrote: fer example, the last one i did-- Dan (always seems to be) twice as old as Mike Mike was 5 years younger than Ben Ben was 10 years younger than Dan Solve for Ben (as the clue) Ben = Dan - 10 Dan = (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| |
| | Re: See what you find when you go snooping around...
|
|
(...) Dan = 2xMike Ben = Mike + 5 Ben = Dan - 10 Substitute for Dan: (2xMike) - 10 = Ben = (Mike + 5) 2xMike - 10 = Mike + 5 Add 10 to each side: 2xMike = Mike + 15 Rewrite as: Mike + Mike = Mike + 15 Subtract a Mike from each side: Mike = 15 (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| |
| | Re: See what you find when you go snooping around...
|
|
(...) I think from here it goes: Ben = (2(Ben) - 10) -10 (dave had an addition sign...) Ben/2(Ben) = 20 1/2 Ben = 20 Ben = 40 .... ? (20 / 1/2) .... DOH! Jeff VW (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| |
| | Re: See what you find when you go snooping around...
|
|
(...) Ben = 2Ben + 10 - 10 Ben - 2Ben = 2Ben - 2Ben + 0 -Ben = 0 Something is wrong here....... (...) Ben = Dan - 10 (susbstitute for Dan) Ben = (Mike x 2) - 10 (substitute for Mike) Ben = 2(Ben - 5) - 10 (solve for ben) Ben = 2Ben - 10 - 10 Ben - (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| |
| | Re: See what you find when you go snooping around...
|
|
(...) Ahh, I see my fallacy-- I went -5 x 2 but applied the same rule as when you multiply two negative numbers!!! (two negative numbers multiplied = positive number) Grr!!! Maybe I need a refresher course in mathematics 101 Oh more than likely... (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
