Subject:
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Re: See what you find when you go snooping around...
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Newsgroups:
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lugnet.org.ca.rtltoronto
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Date:
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Wed, 3 Sep 2003 21:05:39 GMT
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Viewed:
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579 times
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In lugnet.org.ca.rtltoronto, Kevin L. Clague wrote:
> In lugnet.org.ca.rtltoronto, David Koudys wrote:
> > In lugnet.org.ca.rtltoronto, David Koudys wrote:
> >
> > fer example, the last one i did--
> >
> > Dan (always seems to be) twice as old as Mike
> >
> > Mike was 5 years younger than Ben
> >
> > Ben was 10 years younger than Dan
> >
> > Solve for Ben (as the clue)
> >
> > Ben = Dan - 10
> >
> > Dan = Mike x 2
> >
> > Mike = Ben - 5
> >
> >
> > So...
> >
> > Ben = Dan - 10
> > Well, what does Dan =?--substitute...
> >
> > Ben = (Mike x 2) - 10
> > Well, what does Mike =?--substitute
> >
> > Ben = ((Ben - 5) x 2) -10
> >
> > Ben = (2Ben + 10) -10
>
> Ben = 2Ben + 10 - 10
>
> Ben - 2Ben = 2Ben - 2Ben + 0
>
> -Ben = 0
>
> Something is wrong here.......
Ahh, I see my fallacy--
I went -5 x 2 but applied the same rule as when you multiply two negative
numbers!!! (two negative numbers multiplied = positive number)
Grr!!!
Maybe I need a refresher course in mathematics 101
Oh more than likely...
> >
> > Ben = Dan - 10
> >
> > Dan = Mike x 2
> >
> > Mike = Ben - 5
>
> Ben = Dan - 10 (susbstitute for Dan)
>
> Ben = (Mike x 2) - 10 (substitute for Mike)
>
> Ben = 2(Ben - 5) - 10 (solve for ben)
>
> Ben = 2Ben - 10 - 10
>
> Ben - 2Ben = 2Ben - 2Ben - 10 -10
>
> -Ben = -20
>
> Ben = 20
>
> Kevin
Nicely done!
There Chris, you cna solve this problem now!
<snip>
> > Dave K
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