Subject:
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Yet another math problem
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Newsgroups:
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lugnet.off-topic.geek
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Date:
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Mon, 11 Nov 2002 18:15:29 GMT
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Viewed:
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339 times
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This one should be pretty simple for you math-literate folks out there, but
it's giving me a dreadful time...
I have five points and am trying to define the parabola that contains them
(if such exists). The points are:
(0,0) (which is also the vertex)
(14,100)
(-14,100)
(30,180)
(-30,180)
Does a parabola exist to fit those points? And can someone direct me to a
good online walk-thru of the process? I tried a googlesearch for "+parabola
+'three points' +equation" and got about 11,000 hits.
Thanks in advance for your help. If the answer is "no parabola exists" I
can live with it, but I wanted to be sure.
Dave!
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Message has 2 Replies:
 | | Re: Yet another math problem
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| (...) Are you looking for the defining equation of the form y = Ax2+Bx+c ?? or for something else? If the former wouldn't you just solve for "A" and "B" given that "C" is known to be zero (since you said that 0,0 is a point and is the vertex it (...) (22 years ago, 11-Nov-02, to lugnet.off-topic.geek)
| | | Re: Yet another math problem
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| (...) Ugh - I can't believe it takes a math problem to get me to post for the first time in weeks. The formula for a parabola is: y = ax^2 + bx + c You only need three points to define a parabola, but since you've made yours symmetrical about the (...) (22 years ago, 11-Nov-02, to lugnet.off-topic.geek)
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