Subject:
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Re: Yet another math problem
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Newsgroups:
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lugnet.off-topic.geek
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Date:
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Mon, 11 Nov 2002 18:35:35 GMT
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Viewed:
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349 times
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In lugnet.off-topic.geek, Dave Schuler writes:
> This one should be pretty simple for you math-literate folks out there, but
> it's giving me a dreadful time...
>
> I have five points and am trying to define the parabola that contains them
> (if such exists). The points are:
>
> (0,0) (which is also the vertex)
> (14,100)
> (-14,100)
> (30,180)
> (-30,180)
>
> Does a parabola exist to fit those points? And can someone direct me to a
> good online walk-thru of the process? I tried a googlesearch for "+parabola
> +'three points' +equation" and got about 11,000 hits.
>
> Thanks in advance for your help. If the answer is "no parabola exists" I
> can live with it, but I wanted to be sure.
Are you looking for the defining equation of the form
y = Ax2+Bx+c ??
or for something else?
If the former wouldn't you just solve for "A" and "B" given that "C" is
known to be zero (since you said that 0,0 is a point and is the vertex it
implies that, ne?), by substituting in the known values for x and y and
solving the system of simultaneous equations?
I forget. No idea if that helps or not. But I think you have too many points
to be guaranteed it's a parabola. Or maybe not given that they're symmetric
about 0,0.
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Message is in Reply To:
 | | Yet another math problem
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| This one should be pretty simple for you math-literate folks out there, but it's giving me a dreadful time... I have five points and am trying to define the parabola that contains them (if such exists). The points are: (0,0) (which is also the (...) (22 years ago, 11-Nov-02, to lugnet.off-topic.geek)
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