Subject:
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Re: Yet another math problem
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Newsgroups:
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lugnet.off-topic.geek
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Date:
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Mon, 11 Nov 2002 18:39:43 GMT
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Viewed:
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357 times
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In lugnet.off-topic.geek, Dave Schuler writes:
> This one should be pretty simple for you math-literate folks out there, but
> it's giving me a dreadful time...
>
> I have five points and am trying to define the parabola that contains them
> (if such exists). The points are:
>
> (0,0) (which is also the vertex)
> (14,100)
> (-14,100)
> (30,180)
> (-30,180)
>
> Does a parabola exist to fit those points?
Ugh - I can't believe it takes a math problem to get me to post for the
first time in weeks.
The formula for a parabola is:
y = ax^2 + bx + c
You only need three points to define a parabola, but since you've made yours
symmetrical about the y-axis, you're OK.
Your parabola does exist, a = -1/14, b = 57/7, and c=0
Jeff J
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Message has 1 Reply:
 | | Re: Yet another math problem
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| (...) Oops - I'd better correct myself before else does. Your parabola does NOT exist. It is NOT symmetrical. I solved it for the three points with x > 0 My bad. :( Jeff J (22 years ago, 11-Nov-02, to lugnet.off-topic.geek)
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Message is in Reply To:
| | Yet another math problem
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| This one should be pretty simple for you math-literate folks out there, but it's giving me a dreadful time... I have five points and am trying to define the parabola that contains them (if such exists). The points are: (0,0) (which is also the (...) (22 years ago, 11-Nov-02, to lugnet.off-topic.geek)
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