Subject:
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Re: Yet another math problem
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Newsgroups:
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lugnet.off-topic.geek
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Date:
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Mon, 11 Nov 2002 18:54:59 GMT
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Viewed:
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359 times
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In lugnet.off-topic.geek, Jeff Jardine writes:
> >
> > I have five points and am trying to define the parabola that contains them
> > (if such exists). The points are:
> >
> > (0,0) (which is also the vertex)
> > (14,100)
> > (-14,100)
> > (30,180)
> > (-30,180)
>
>
> Your parabola does exist, a = -1/14, b = 57/7, and c=0
Oops - I'd better correct myself before else does.
Your parabola does NOT exist. It is NOT symmetrical. I solved it for the
three points with x > 0
My bad. :(
Jeff J
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Message has 1 Reply:
Message is in Reply To:
 | | Re: Yet another math problem
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| (...) Ugh - I can't believe it takes a math problem to get me to post for the first time in weeks. The formula for a parabola is: y = ax^2 + bx + c You only need three points to define a parabola, but since you've made yours symmetrical about the (...) (22 years ago, 11-Nov-02, to lugnet.off-topic.geek)
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