 | | Re: See what you find when you go snooping around... —Chris Magno
|
| | | (...) huh? algebra? is that like fake numbers and all that phooey? hummm. let me do some search on line for... how do you say.... algebra. I mean any word with bra in it has to be cool right? (...) I use variables like X, Y & Z. in fact all my (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| | | |
| | | | | Re: See what you find when you go snooping around... —David Koudys
|
| | | | In lugnet.org.ca.rtltoronto, Chris Magno wrote: <snip> (...) rtlToronto's problem solving--get yer 'bot to do this! No problem Algebra's not a problem, it's hell. ;) But I always seem to work 'em out. So far, have gotten thru most of the building at (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| | | | |
| | | | | | Re: See what you find when you go snooping around... —David Koudys
|
| | | | In lugnet.org.ca.rtltoronto, David Koudys wrote: fer example, the last one i did-- Dan (always seems to be) twice as old as Mike Mike was 5 years younger than Ben Ben was 10 years younger than Dan Solve for Ben (as the clue) Ben = Dan - 10 Dan = (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| | | | |
| | | | | | Re: See what you find when you go snooping around... —John Gerlach
|
| | | | | (...) Dan = 2xMike Ben = Mike + 5 Ben = Dan - 10 Substitute for Dan: (2xMike) - 10 = Ben = (Mike + 5) 2xMike - 10 = Mike + 5 Add 10 to each side: 2xMike = Mike + 15 Rewrite as: Mike + Mike = Mike + 15 Subtract a Mike from each side: Mike = 15 (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| | | | | |
| | | | | | Re: See what you find when you go snooping around... —Jeff Van Winden
|
| | | | | (...) I think from here it goes: Ben = (2(Ben) - 10) -10 (dave had an addition sign...) Ben/2(Ben) = 20 1/2 Ben = 20 Ben = 40 .... ? (20 / 1/2) .... DOH! Jeff VW (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| | | | | |
| | | | | | Re: See what you find when you go snooping around... —Kevin L. Clague
|
| | | | (...) Ben = 2Ben + 10 - 10 Ben - 2Ben = 2Ben - 2Ben + 0 -Ben = 0 Something is wrong here....... (...) Ben = Dan - 10 (susbstitute for Dan) Ben = (Mike x 2) - 10 (substitute for Mike) Ben = 2(Ben - 5) - 10 (solve for ben) Ben = 2Ben - 10 - 10 Ben - (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| | | | |
| | | | | | Re: See what you find when you go snooping around... —David Koudys
|
| | | | (...) Ahh, I see my fallacy-- I went -5 x 2 but applied the same rule as when you multiply two negative numbers!!! (two negative numbers multiplied = positive number) Grr!!! Maybe I need a refresher course in mathematics 101 Oh more than likely... (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
|
| | | | |
