Subject:
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Re: some 'puter/math help please
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Newsgroups:
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lugnet.org.ca.rtltoronto
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Date:
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Fri, 23 Mar 2007 14:10:21 GMT
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Viewed:
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1480 times
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In lugnet.org.ca.rtltoronto, Rafe Donahue wrote:
<snip>
> Does that help?
>
> Rafe
actually, that helps quite a bit! I thought I'd have to get pythagoras in the
equatinos somehow, but htis is much easier!
Much appreciated!
> p.s. Oops, I just saw that you want to go from 10 down to 0. In that case, set
> up the loop to go from, say, 10 to 0 with a step of -10/k instead of 10/k.
It'll be a wide range of starting points, but 1 ending point, but with your
explanations, I'll be able to do what I want :)
Again, thanks!
Dave K
-who should have paid more attention in math class back when he was in school...
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Message is in Reply To:
 | | Re: some 'puter/math help please
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| (...) The points on the line take the form y = mx + b, where b is the intercept with the y-axis and m is the slope. For the problem as you describe it, b is 0 since the line crosses the y-axis at zero, and m = 1.5 or 15/10 since the slope is the (...) (18 years ago, 23-Mar-07, to lugnet.org.ca.rtltoronto)
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