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Scott, Can you post and example of the type of queries you have been trying? I know you said they where giving you errors, but at least we'd have an idea of what you are trying to do. jt (...) (22 years ago, 7-Mar-03, to lugnet.off-topic.geek)
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| | Access Help
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To All, I have been working on a project at work for over a year now, converting an Excel Production Recap program into an Access program. I have been successful converting it, outside of some small issues, which I have finally resolved in the last (...) (22 years ago, 7-Mar-03, to lugnet.off-topic.geek)
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| | Re: Now the stakes are higher....
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(...) Effectively, he's right but he's not giving things the probability they're due. In his solution, the (r1 r2) choice is GUARANTEED that no matter which one you reveal (r1 or r2), the one revealed will be red. However, with, say, (r1 b), there's (...) (22 years ago, 6-Mar-03, to lugnet.off-topic.geek)
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| | Re: Now the stakes are higher....
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In lugnet.off-topic.geek, David Eaton writes: <snip> (...) That's perfect! I owe you a lunch! Now whetehr or not my co-worker succumbs to 'outside sources' as valid enuf to change his position remains to be seen I'm trying to explain his fallacy and (...) (22 years ago, 6-Mar-03, to lugnet.off-topic.geek)
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| | Re: Now the stakes are higher....
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(...) HA! Congrats on winning 100 bucks :) (...) Proof number one: (pure stats) #!/usr/bin/perl for(1..1000) { @marbles = ("r","r","b","w"); $pick = ''; for(1..2) { $n = int rand(@marbles); $pick .= $marbles[$n]; splice @marbles,$n,1; } $tot++; (...) (22 years ago, 6-Mar-03, to lugnet.off-topic.geek)
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| | Now the stakes are higher....
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So now he says he's willing to put 100 dollars on the 1 in 5... I'm swayed back to the 1 in 3... So here's the original question-- If you have 4 marbles in a bag, 2 are red, 1 is blue, 1 is white You grab 2 marbles from the bag at the same time One (...) (22 years ago, 6-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) Didn't mean to offend. Sorry 'bout that. I read the site thru again and your synopsis of the explanation above and I concur that it should be 2/3, but I like to work things thru... :) If I were to walk in off the street right after one of the (...) (22 years ago, 5-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) Ok, here's where I'll take it from. The car is behind one of the doors, so the probabilities must add up to 1. 3 doors, 1/3 of a chance for each door. You pick door 1. There is a 1 in 3 chance the car is behind that door. There is a 2 in 3 (...) (22 years ago, 5-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) Saw that ;) but understood... but if we're talking one instance--one event--and that's what we're, indeed, talking about--you are on a game show, one event--you have one chance of winning one car behind one door.... so you have 3 doors I won't (...) (22 years ago, 5-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) Saw that ;) but understood... but if we're talking one instance--one event--and that's what we're, indeed, talking about--you are on a game show, one event--you have one chance of winning one car behind one door.... so you have 3 doors I won't (...) (22 years ago, 5-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) I think it's a great idea! Dave K (22 years ago, 5-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) This analysis assumes there is a percievable difference between the red balls, which as originally stated, there isn't. It's similar to the difference between combinations and permutations. The two permutations you've listed with a red ball in (...) (22 years ago, 4-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) If you keep going on and on and on... well I probably still will, unless someone explains why I should not. (22 years ago, 4-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) Bleargh! typo. r2 w (r1 is the only red ball, it is removed) (...) (22 years ago, 4-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) Why not? There are two different red balls, so each of those red balls is equally likely as the white ball to be in my hand. (...) No, because you only tried to remove r2. We are only removing *a* red ball from the bag; because there are 2 red (...) (22 years ago, 4-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) Clear as mud, for then if the red is irrelevant, then there cannot be (...) there can only be (...) for if we remove either red ball from the bag, that very same red ball in this specific instance cannot be in the person's hand. We cannot take (...) (22 years ago, 4-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) Basically, each column decreases in liklihood as more choices are added. Start with one colum: Prob. Prize 1/3 1 1/3 2 1/3 3 Now, you get to choose a door. Since the prize door doesn't affect the probability: Prob. Prize Choice 1/9 1 1 1/9 1 2 (...) (22 years ago, 4-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) Nope, you're assuming that the marble pulled out of the bag is r2. It might be r1. Better to leave off the numbers, as the red marbles are not distinct. hand bag r r w r r w w r r remove a red from the bag and it reduces to: hand bag r w r w w (...) (22 years ago, 4-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) I think I may have found the fallacy... (indulge me if you please) Here's a bag with 3 marbles in it--2 are red (goats, whatever), one is white (brand new car) Pick a random one out of the bag and hold it in your hand--don't look at it! What's (...) (22 years ago, 4-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) This one here? (URL) many trials? It is a *probability* after all, no guarantees about a short run of trials. I ran 30 "stay" and 30 "switch" and got roughly 40 and 60 as the two percentage results. Moving to the serious number cruncher, which (...) (22 years ago, 4-Mar-03, to lugnet.off-topic.geek)
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