 | | Re: Yet another math problem
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(...) Sorry, but this doesn't go through 0,0. Solving x=0, y=0 gives 0=855/11, which is clearly not true, so this isn't the equation he's looking for either. Adrian -- www.brickfrenzy.com (22 years ago, 11-Nov-02, to lugnet.off-topic.geek)
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| | Re: Yet another math problem
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(...) Yes, it does. If you just have the last four points to work with, then you definitely have an upward-turned parabola, symmetrical about the y-axis. Here's what you have to do to find the formula for a parabola, given three points: y = ax^2 + (...) (22 years ago, 11-Nov-02, to lugnet.off-topic.geek)
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| | Re: Comparative freedom
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(...) Actually, they did not told the Queen to bugger off... because they did not have to; they got their own PM instead. Given that the Crown has little (if any) effective power, it is even better: getting independent whilst assuring a powerful (...) (22 years ago, 11-Nov-02, to lugnet.off-topic.debate)
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| | Re: Yet another math problem
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(...) Hmm. Well, now that I think of it, the vertex could be x=0 with y as an unknown. Does that change anything? Dave! (22 years ago, 11-Nov-02, to lugnet.off-topic.geek)
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| | Re: Yet another math problem
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(...) Oops - I'd better correct myself before else does. Your parabola does NOT exist. It is NOT symmetrical. I solved it for the three points with x > 0 My bad. :( Jeff J (22 years ago, 11-Nov-02, to lugnet.off-topic.geek)
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| | Living in America--was Re: Comparative freedom
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In lugnet.off-topic.debate, Bruce Schlickbernd writes: <snip> (...) *If* I were to live in the USofA... (and that's a mighty big *if*)... I'd want to live in sunny SoCal... I love it when Craiggers does the "What's the weather like in Buffalo this (...) (22 years ago, 11-Nov-02, to lugnet.off-topic.debate)
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| | Testing
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tset Fredrik (22 years ago, 11-Nov-02, to lugnet.off-topic.test)
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| | Re: Yet another math problem
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(...) Ugh - I can't believe it takes a math problem to get me to post for the first time in weeks. The formula for a parabola is: y = ax^2 + bx + c You only need three points to define a parabola, but since you've made yours symmetrical about the (...) (22 years ago, 11-Nov-02, to lugnet.off-topic.geek)
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| | Re: Yet another math problem
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(...) Are you looking for the defining equation of the form y = Ax2+Bx+c ?? or for something else? If the former wouldn't you just solve for "A" and "B" given that "C" is known to be zero (since you said that 0,0 is a point and is the vertex it (...) (22 years ago, 11-Nov-02, to lugnet.off-topic.geek)
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| | Yet another math problem
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This one should be pretty simple for you math-literate folks out there, but it's giving me a dreadful time... I have five points and am trying to define the parabola that contains them (if such exists). The points are: (0,0) (which is also the (...) (22 years ago, 11-Nov-02, to lugnet.off-topic.geek)
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