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In lugnet.events.brickworld, Brian Davis wrote:
> Brickworld 2007, June 21-24, Chicago
>
> Indy 5.00:
>
> Autonomous robots will run head-to-head races of five laps around a 8’x10’ oval
> gradient track.
>
> Arena:
>
> The oval will be centered on a 4’ by 8’ surface, with no rails or other physical limits.
Okay, I'm confused. How can an 8' x 10' track be centered on a 4' by 8'
surface? What is the actual width of the track? If the whole track fits on a
4' x 8' surface, then I would assume the width must be less then 2'.
Gus
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Message has 2 Replies:
 | | Re: Brickworld 2007 - Indy 5.00
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| (...) Seems clear to me :) there will be magic.... Actually - looks like a really wacky typo. Hopefully Steve H or Brian D jumps in to clarify for certain. But, I believe the full track layout is 4' x 8'. So, the track itself is just under 2' wide. (...) (17 years ago, 17-Jun-07, to lugnet.events.brickworld, lugnet.robotics)
| | | Re: Brickworld 2007 - Indy 5.00
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| (...) That appears to be a typo. The track fits on a FLL table, so it's a 44"x92" inch oval. And the lane is about 2ft wide. It's pretty easy to build and program a robot for this event. It just needs to follow a specific shade (actual value will (...) (17 years ago, 17-Jun-07, to lugnet.events.brickworld, lugnet.robotics)
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Message is in Reply To:
| | Brickworld 2007 - Indy 5.00
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| Brickworld 2007, June 21-24, Chicago Indy 5.00: Autonomous robots will run head-to-head races of five laps around a 8’x10’ oval gradient track. The event will be double-elimination or round-robin style (depending on the number of participants; (...) (18 years ago, 18-Apr-07, to lugnet.events.brickworld, lugnet.robotics)
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