 | | Re: icosahedron in soccer-ball style —John Gerlach
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| | | (...) Yup, I realize that now. Holding the big ball in your hands can really make those ideas clear! The problem is, how to do it within the limits of the "Lego System"? I want to experiment with other triangle sizes, and see what happens and what (...) (21 years ago, 15-Sep-03, to lugnet.build.sculpture, FTX)
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| | | | | Re: icosahedron in soccer-ball style —Philippe Hurbain
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| | | | | (...) Originally I thought of using 2x1 plates with one stud to get a 1/2 stud value, but your 6/5/5 idea is probably (much) better. The precise value is 6/5.1/5.1 so here the pentagons will be taut and flat. There is probably enough slack in the (...) (21 years ago, 15-Sep-03, to lugnet.build.sculpture, FTX)
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| | | | | | | Re: icosahedron in soccer-ball style —Philippe Hurbain
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| | | | | | (...) Well... I tried to build a pentagon (using solid 2x5 structures in the middle) and I was not able to close it (too much tension). Perhaps with the bar and holes it would work ? Philo (21 years ago, 15-Sep-03, to lugnet.build.sculpture, FTX)
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| | | | | Re: icosahedron in soccer-ball style —Alan Findlay
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| | | | (...) I don't have the parts to try this out, so my suggestion may be highly disposable. How about making each black triangle a 4/3/4? By this I mean: each black/white join would be 4/4, and each black/black join would be 4/3. The pentagon wouldn't (...) (21 years ago, 16-Sep-03, to lugnet.build.sculpture, FTX)
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| | | | | | Re: icosahedron in soccer-ball style —John Gerlach
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| | | | (...) I tried 4/3/3 - but it didn't work. The triangles couldn't connect to form the pentagon. The other problem is since I'm using the 1x4 hinge plates, if you go shorter than four studs on a side of the triangle you have to come up with a (...) (21 years ago, 16-Sep-03, to lugnet.build.sculpture, FTX)
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| | | | | | Re: icosahedron in soccer-ball style —Alan Findlay
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| | | | Well, that's weird. My original message said: (...) But you're copy of it said: (...) I wonder how that got mixed up? < shrug > Anyway, back to my original idea. The reason I had suggested 4/3/4 was based on Phillippe's formula of 4/3.5/3.5 -- (...) (21 years ago, 16-Sep-03, to lugnet.build.sculpture, FTX)
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| | | | | | Re: icosahedron in soccer-ball style —John Gerlach
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| | | | | (...) I changed it, because I was thinking you meant that each of the black triangles would have one side of length 4 (that connects to the white hexagon), and two sides of length 3 (that connect to the two ajoining black triangles within the (...) (21 years ago, 16-Sep-03, to lugnet.build.sculpture, FTX)
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| | | | | | | Re: icosahedron in soccer-ball style —Alan Findlay
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| | | | | | (...) Hoo, boy. How to explain without pictures? Hmmm... okay here goes... Suppose the following represented two black triangles set side by side, touching at one vertices... _ _ \/ \/ The sides represented by "_" are 1x4's connecting to white 1x4's (...) (21 years ago, 16-Sep-03, to lugnet.build.sculpture)
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| | | | | | | | Re: icosahedron in soccer-ball style —John Gerlach
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| | | | | | Ok, now I understand what you're going for. Interesting idea! And I can imagine why you refered to it as a "pinwheel"... :-) I was stuck on using the equalateral triangles due to me having a large collection of (URL) Polydron> (gasp! A different (...) (21 years ago, 16-Sep-03, to lugnet.build.sculpture, FTX)
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| | | | | | Re: icosahedron in soccer-ball style —Philippe Hurbain
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| | | | (...) Or you can go simpler: if you suppress the triangles inside the pentagon, the problem disappear! But the structure may look somewhat hollow... Philo (21 years ago, 16-Sep-03, to lugnet.build.sculpture, FTX)
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