Subject:
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Re: Mechanical question
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Newsgroups:
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lugnet.robotics
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Date:
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Tue, 27 Jul 1999 21:05:14 GMT
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Original-From:
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Paul Speed <pspeed@augustschell.SPAMLESScom>
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Viewed:
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1072 times
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Jon Shemitz wrote:
>
> Laurentino Martins wrote:
>
> > Also important in all this is the distance the tracks are apart. The further apart the less friction they have, since the radius is larger.
> > Same happens with wheels.
>
> Why is this? The further apart they are, the greater r*cos(theta) is
> going to be for any given theta. Seems like that would make for more
> turning resistance, not less.
Because the wheel base length shrinks in relation to the
turning radius. It is this distance that causes the friction. The
further this point is from the imaginary circle that the treads
describe, the more perpendicular friction there is. As the turning
radius increases and the tread length stays the same, the tread
more closely approximates this imaginary circle.
If necessary I can probably even show it mathematically.
-Paul (pspeed@progeeks.com, http://www.progeeks.com/)
--
Did you check the web site first?: http://www.crynwr.com/lego-robotics
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Message has 2 Replies:
 | | Re: Mechanical question
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| (...) Sure. Based on other comments I've received I'm guessing my previous explaination was a little obtuse. (No pun intended... angles, get it.) Ok, let's see if I can explain this without any pretty pictures. It is getting to be time for bed so (...) (25 years ago, 28-Jul-99, to lugnet.robotics)
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Message is in Reply To:
| | Re: Mechanical question
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| (...) Why is this? The further apart they are, the greater r*cos(theta) is going to be for any given theta. Seems like that would make for more turning resistance, not less. (25 years ago, 27-Jul-99, to lugnet.robotics)
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