Subject:
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Re: why doesn't this work?
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Newsgroups:
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lugnet.robotics
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Date:
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Tue, 30 Nov 2004 23:19:34 GMT
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Viewed:
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1048 times
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In lugnet.robotics, Steve Hassenplug wrote:
> > In lugnet.robotics, Steve Hassenplug wrote:
> >
> > > What is the value of inc when you're done?
> >
> > 2000
>
> I think that means for the first 27 times through the loop, the value for SENSOR_1
> changes every time. So all the values would be 0 or 1.
>
> Instead of storing the timeout, try creating a seperate counter that's incromented
> each time through the loop, and store that in the array. It may turn out to be a
> sequence of numbers.
>
> I think the program is working.
>
> Steve
Your exactly right, the results are a sequence 1-20, meaning that it takes 20
sensor changes to go from full speed to stop. The rest of the array is zero's as
it should be, so the program works perfectly.
I'm amazed though that the rotation sensor can change more quickly than the
program can loop,
I think I'll have to change to the faster firmware. I haven't yet, as the bugs
I've yet to develop out are easier to spot using the standard firmware.
Thanks
If anyone has a smooth decelaration algorithm, I'd be very interested to see it.
Steve
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Message has 1 Reply:
 | | Re: why doesn't this work?
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| (...) That doesn't totally seem right. I would think it would slow, before stoping. One last thing to try is actually storing sensor value in the array. Also, in the Checkvar function, it looks like the line: if(temp<27) temp=0; should say (...) (20 years ago, 1-Dec-04, to lugnet.robotics)
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Message is in Reply To:
| | Re: why doesn't this work?
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| (...) I think that means for the first 27 times through the loop, the value for SENSOR_1 changes every time. So all the values would be 0 or 1. Instead of storing the timeout, try creating a seperate counter that's incromented each time through the (...) (20 years ago, 30-Nov-04, to lugnet.robotics)
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