 | | Re: See what you find when you go snooping around...
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In lugnet.org.ca.rtltoronto, David Koudys wrote: fer example, the last one i did-- Dan (always seems to be) twice as old as Mike Mike was 5 years younger than Ben Ben was 10 years younger than Dan Solve for Ben (as the clue) Ben = Dan - 10 Dan = (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
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| | Re: See what you find when you go snooping around...
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(...) Dan = 2xMike Ben = Mike + 5 Ben = Dan - 10 Substitute for Dan: (2xMike) - 10 = Ben = (Mike + 5) 2xMike - 10 = Mike + 5 Add 10 to each side: 2xMike = Mike + 15 Rewrite as: Mike + Mike = Mike + 15 Subtract a Mike from each side: Mike = 15 (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
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| | Re: See what you find when you go snooping around...
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(...) I think from here it goes: Ben = (2(Ben) - 10) -10 (dave had an addition sign...) Ben/2(Ben) = 20 1/2 Ben = 20 Ben = 40 .... ? (20 / 1/2) .... DOH! Jeff VW (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
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| | Re: See what you find when you go snooping around...
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(...) Ben = 2Ben + 10 - 10 Ben - 2Ben = 2Ben - 2Ben + 0 -Ben = 0 Something is wrong here....... (...) Ben = Dan - 10 (susbstitute for Dan) Ben = (Mike x 2) - 10 (substitute for Mike) Ben = 2(Ben - 5) - 10 (solve for ben) Ben = 2Ben - 10 - 10 Ben - (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
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| | Re: See what you find when you go snooping around...
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(...) Ahh, I see my fallacy-- I went -5 x 2 but applied the same rule as when you multiply two negative numbers!!! (two negative numbers multiplied = positive number) Grr!!! Maybe I need a refresher course in mathematics 101 Oh more than likely... (...) (21 years ago, 3-Sep-03, to lugnet.org.ca.rtltoronto)
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