 | | Re: On a scale of 0 to 10?
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(...) Oh yeah! (...) Oh... yeah. (...) Hm. Double checked the math-- it appears solid [1], which would mean that there's no viable solution for: s = Ae^(q + B) + C for coordinates (-1,0), (0,5), (0.25,10). Darn. Hm. I guess that also means that any (...) (22 years ago, 26-Mar-03, to lugnet.off-topic.geek)
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| | Re: On a scale of 0 to 10?
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(...) *snip* (...) summed exponents like that can be re-written in this way: e^B * e^.25 + e^B * e^-1 = 2e^B (e^.25 + e^-1) * e^B = 2e^B Uh oh. Divide both sides by e^B and we've got (e^.25 + e^-1) = 2 1.652 = 2 Which ain't right. I think your math (...) (22 years ago, 26-Mar-03, to lugnet.off-topic.geek)
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| | Re: On a scale of 0 to 10?
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(...) Thought about that... If necessary I guess, but I'm pretty sure there's a way to do it. I think what I need is: s = Ae^(q + B) + C And at the moment, I've solved: C = -Ae^(B - 1) A = 10 / (e^(B + .25) - e^(B - 1)) And I'm scratching my head (...) (22 years ago, 26-Mar-03, to lugnet.off-topic.geek)
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| | Re: On a scale of 0 to 10?
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(...) How about a double-linear solution? from -1 to 0, translate linearly from 0 to 5. From 0 to .25, translate linearly from 5 to 10. You won't have a single equation, but that seems to accomplish what you want, right? Adrian (22 years ago, 26-Mar-03, to lugnet.off-topic.geek)
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| | On a scale of 0 to 10?
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I've got a function that represents a quality rating, based on 2 parameters, which are on a scale of 0 to 1: (d-k)*k => quality (q) Notice that this yields a sort of wacky result, insofar as the quality can vary between -1 and 0.25, not -1 and 1 or (...) (22 years ago, 26-Mar-03, to lugnet.off-topic.geek)
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| | Re: Website move
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(...) The domain name is the fully qualified host name. If you need DNS to look it up, it's a domain name - the "host" in the RFC. That's what it's a "Domain Name Service" :) Anything after the / is part of the path, as defined in the HTTP RFC (...) (22 years ago, 26-Mar-03, to lugnet.space, lugnet.publish, lugnet.off-topic.geek)
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| | Re: Backwards Compatibility (Was Calling all Meta-commands)
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(...) ROFL. I'm sorry, I can't reply in kind. My brain is too fogged. Steve (22 years ago, 22-Mar-03, to lugnet.off-topic.geek)
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| | Re: Backwards Compatibility (Was Calling all Meta-commands)
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(...) you mean $puctuation++ > ! $puctuation ? $goodness++ : $goodness-- ; ? (22 years ago, 22-Mar-03, to lugnet.cad.dev, lugnet.off-topic.geek)
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| | Re: connect four
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(...) This interested me for a while-- I wrote a recursive program once that would look X ply into the game, though because I never stored state information, it took ridiculously exponentially longer with each value of X. Something like 6 ply was (...) (22 years ago, 19-Mar-03, to lugnet.org.ca.rtltoronto, lugnet.off-topic.geek)
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| | Re: Access Help
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James & All, (...) Yes, I have a total query, where it is running a sum of all the data from a date range (say 1/1/02 to 12/31/02 or whatever). The value I am trying to evaluate is a calculated sum of various percentages of our recovery numbers, in (...) (22 years ago, 7-Mar-03, to lugnet.off-topic.geek)
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