Subject:
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Re: circular pointer
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Newsgroups:
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lugnet.robotics
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Date:
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Mon, 14 May 2007 05:08:00 GMT
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Original-From:
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linmix <linmix@gmail.!Spamless!com>
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Viewed:
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4887 times
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Dennis Williamson wrote:
> In lugnet.robotics, linmix <linmix@gmail.com> wrote:
> [snip]
>
> > So by defining SIZE here I can easily change the size of the macro
> > without having to alter anything else in the code. Nice!
>
> [snip]
>
> I would say defining SIZE changes the size of the array and thus the period of
> the moving average. I'm not sure how you mean "macro" in this context.
I should have written: 'array'
> [snip]
>
> > > v[i]=0;
> >
> > Is it necessary to initialise v[2] or simply 'cleaner' coding?
> >
> > > while (true) //** Do it forever
> > > {
> > > sum -= v[i];
> > >
> > >
>
> Yes, both necessary and cleaner. If you don't initialize v[2] then the first
> statement in the while loop evaluates to "sum = sum - UNDEFINED;" which could be
> anything. In many cases, it'll be zero, but it's better to be certain.
>
> Often, variables are declared and initialized at the same time. Thus:
>
> int i, j = 0;
> int v[3] = {1, 2, 3};
OK, undefined is not the same as zero, that makes sense (in a way).
I looked up how to initialise an array and according to Dave Baum's NQC
Guide "The initial values for an array's elements cannot be specified -
an explicit assignment is required within the program itself to set the
value of an element."
> (syntax approximate)
>
> But when using a #define or when the array is large it can work better to
> initialize an array with a loop.
So indeed a loop would be the thing
Thank you for your time and detailed explanations!
Linmix
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Message is in Reply To:
 | | Re: circular pointer
|
| In lugnet.robotics, linmix <linmix@gmail.com> wrote: [snip] (...) [snip] I would say defining SIZE changes the size of the array and thus the period of the moving average. I'm not sure how you mean "macro" in this context. [snip] (...) Yes, both (...) (17 years ago, 13-May-07, to lugnet.robotics)
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