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Calum Tsang wrote:
> heck, there are people who use millimeters here.
Oh my, I almost forgot! I should have done all those calculations in SI!
Well, let me correct my mistake:
There are 3.048 feet in 1 meter.*
Hence, 8 feet / 3.048 feet/meter = 2.625 meters.
And also, 2 feet / 3.048 feet/meter = 0.6562 meters.
Therefore, by the Pythagorean Theorem, the distance diagonally across
the playfield is 3.712 m, and the distance across the block in the
middle is 0.9280 m.
(Wait a minute. Is wood measured in US Survey feet, or international feet?)
Now, if the pedestal is not turned (ie, its sides are parallel to the
walls of the arena), then the distance from the corner of the arena to
the pedestal is:
3.712 m / 2 - 0.9280 m / 2 = 1.392 m
And if the the pedestal is turned (which is my preference):
3.712 m / 2 - 0.3048 m = 1.551 m
But I could be wrong.
* Conversion factor obtained from http://physics.nist.gov/Document/sp811.pdf
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Message has 1 Reply:
 | | Re: rtl 13 rules
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| Um, Trevyn, I hate to rain on your parade, and all, but there are ~3.28 feet in a meter. That might throw off your calculations a bit. Well, truth be told, it did. The reference you gave states on page 42 that 1ft = 3.048 E-01 m That is, there are (...) (22 years ago, 5-Dec-02, to lugnet.org.ca.rtltoronto)
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Message is in Reply To:
| | Re: rtl 13 rules
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| (...) I actually remembered that last night. I don't really care each way-having you attack on a corner is moderately more difficult, but not really. I think we've established a precedent to make things less easy for the sake of it, but I'm (...) (22 years ago, 4-Dec-02, to lugnet.org.ca.rtltoronto)
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