To LUGNET HomepageTo LUGNET News HomepageTo LUGNET Guide Homepage
 Help on Searching
 
Post new message to lugnet.off-topic.geekOpen lugnet.off-topic.geek in your NNTP NewsreaderTo LUGNET News Traffic PageSign In (Members)
 Off-Topic / Geek / 4967
4966  |  4968
Subject: 
Re: [OT] How large would Executor-class SSD appear?
Newsgroups: 
lugnet.starwars, lugnet.off-topic.geek
Date: 
Tue, 15 Feb 2005 19:38:02 GMT
Viewed: 
71 times
  
In lugnet.starwars, James Wilson wrote:
So, here's what I got (keep in mind that the Moon and Sun subtend about 1
degree of arc in the sky):
Geostationary orbit (22,223 mi.):  0.028 deg.
Hubble Telescope orbit (320 mi.):  1.958 deg. - twice the width of the full
Moon.
"Edge of Space" (62 miles):        10.08 deg. - now we're getting somewhere!
50,000 ft:                         60.01 deg.

I'm not sure what to do with this, but I was surprised at how small something
so (fictionally) large would appear in the sky.

I dunno, it sounds like it makes sense. I mean, imagine how big a Boeing 747
looks at 50,000 feet (I get about 1/8th of a degree, assuming 70.7m length for a
747). Actually, considering how crasily long many clouds are, I wouldn't be
suprised to learn that they're the size of the SSD :)

DaveE



Message is in Reply To:
  [OT] How large would Executor-class SSD appear?
 
OK, this is WAY geeky, but I just thought I'd share... This was triggered by a cloud visible at sunset a couple of evenings ago. It was long and triangular, and took up about 5 "hand-widths" at arms length. I started thinking, how close (or far (...) (20 years ago, 15-Feb-05, to lugnet.starwars, lugnet.off-topic.geek)

7 Messages in This Thread:




Entire Thread on One Page:
Nested:  All | Brief | Compact | Dots
Linear:  All | Brief | Compact
    

Custom Search

©2005 LUGNET. All rights reserved. - hosted by steinbruch.info GbR