 | | Re: Access Help
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Scott, Can you post and example of the type of queries you have been trying? I know you said they where giving you errors, but at least we'd have an idea of what you are trying to do. jt (...) (22 years ago, 7-Mar-03, to lugnet.off-topic.geek)
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| | Access Help
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To All, I have been working on a project at work for over a year now, converting an Excel Production Recap program into an Access program. I have been successful converting it, outside of some small issues, which I have finally resolved in the last (...) (22 years ago, 7-Mar-03, to lugnet.off-topic.geek)
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| | Re: Now the stakes are higher....
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(...) Effectively, he's right but he's not giving things the probability they're due. In his solution, the (r1 r2) choice is GUARANTEED that no matter which one you reveal (r1 or r2), the one revealed will be red. However, with, say, (r1 b), there's (...) (22 years ago, 6-Mar-03, to lugnet.off-topic.geek)
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| | Re: Now the stakes are higher....
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In lugnet.off-topic.geek, David Eaton writes: <snip> (...) That's perfect! I owe you a lunch! Now whetehr or not my co-worker succumbs to 'outside sources' as valid enuf to change his position remains to be seen I'm trying to explain his fallacy and (...) (22 years ago, 6-Mar-03, to lugnet.off-topic.geek)
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| | Re: Now the stakes are higher....
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(...) HA! Congrats on winning 100 bucks :) (...) Proof number one: (pure stats) #!/usr/bin/perl for(1..1000) { @marbles = ("r","r","b","w"); $pick = ''; for(1..2) { $n = int rand(@marbles); $pick .= $marbles[$n]; splice @marbles,$n,1; } $tot++; (...) (22 years ago, 6-Mar-03, to lugnet.off-topic.geek)
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| | Now the stakes are higher....
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So now he says he's willing to put 100 dollars on the 1 in 5... I'm swayed back to the 1 in 3... So here's the original question-- If you have 4 marbles in a bag, 2 are red, 1 is blue, 1 is white You grab 2 marbles from the bag at the same time One (...) (22 years ago, 6-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) Didn't mean to offend. Sorry 'bout that. I read the site thru again and your synopsis of the explanation above and I concur that it should be 2/3, but I like to work things thru... :) If I were to walk in off the street right after one of the (...) (22 years ago, 5-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) Ok, here's where I'll take it from. The car is behind one of the doors, so the probabilities must add up to 1. 3 doors, 1/3 of a chance for each door. You pick door 1. There is a 1 in 3 chance the car is behind that door. There is a 2 in 3 (...) (22 years ago, 5-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) Saw that ;) but understood... but if we're talking one instance--one event--and that's what we're, indeed, talking about--you are on a game show, one event--you have one chance of winning one car behind one door.... so you have 3 doors I won't (...) (22 years ago, 5-Mar-03, to lugnet.off-topic.geek)
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| | Re: math question (or pattern... whatever...)
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(...) Saw that ;) but understood... but if we're talking one instance--one event--and that's what we're, indeed, talking about--you are on a game show, one event--you have one chance of winning one car behind one door.... so you have 3 doors I won't (...) (22 years ago, 5-Mar-03, to lugnet.off-topic.geek)
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