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Suppose I have a triangle, in which I know the lengths of the three
sides. I want to find the corresponding angles inside the triangles.
Is there a quick and simple way to do that?
I know that I can divide the triangle into two triangles with a 90°
angle each, and then solve a set of two equations with two unknowns.
But that is a bit of a hassle, especially if there is a simpler way.
Fredrik
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Message has 1 Reply:
 | | Re: Geometry
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| (...) Reaching way, way back... Can you use the law of sines? sin A / a = sin B / b = sin C / c Seems like there's a step missing though. Perhaps the law of cosines is better: a*a + b*b + c*c = -2bc*cos(A) Solve for A? Anyhow, good luck. Don (25 years ago, 28-Jul-99, to lugnet.off-topic.geek)
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