Subject:
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Re: Geometry
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Newsgroups:
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lugnet.off-topic.geek
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Date:
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Wed, 28 Jul 1999 16:49:03 GMT
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Viewed:
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134 times
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In lugnet.off-topic.geek, Fredrik Glöckner writes:
> Suppose I have a triangle, in which I know the lengths of the three
> sides. I want to find the corresponding angles inside the triangles.
> Is there a quick and simple way to do that?
>
> I know that I can divide the triangle into two triangles with a 90°
> angle each, and then solve a set of two equations with two unknowns.
> But that is a bit of a hassle, especially if there is a simpler way.
>
> Fredrik
Reaching way, way back... Can you use the law of sines?
sin A / a = sin B / b = sin C / c
Seems like there's a step missing though.
Perhaps the law of cosines is better:
a*a + b*b + c*c = -2bc*cos(A)
Solve for A?
Anyhow, good luck.
Don
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Message has 1 Reply:
 | | Re: Geometry
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| (...) With a, b and c being the length of the sides, and A being the angle of the edge just opposite of a? Why, that looks just perfect! Thanks! (I'm used to using A, B and C for the lengths and the corresponding lowercase letters for the angles, so (...) (25 years ago, 29-Jul-99, to lugnet.off-topic.geek)
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Message is in Reply To:
| | Geometry
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| Suppose I have a triangle, in which I know the lengths of the three sides. I want to find the corresponding angles inside the triangles. Is there a quick and simple way to do that? I know that I can divide the triangle into two triangles with a 90° (...) (25 years ago, 28-Jul-99, to lugnet.off-topic.geek)
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