Subject:
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Re: CO BrikWars get together
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Newsgroups:
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lugnet.loc.us.oh
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Date:
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Thu, 13 Apr 2000 13:35:39 GMT
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Viewed:
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1906 times
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In lugnet.loc.us.oh, Shaun Sullivan writes:
>
> As for hieght, we used a brick (brik?) as being one unit. For 'mechs, we took the
> torso, and multiplied the larger two of the three dimensions. So a tall skinny
> 4x2x6 (width, depth, height) torso would cost as much as a short squat fatty
> 6x4x2. For applying movement and cost, we considered them to be treaded ground
> vehicles (we considered the Brikwars 2000 'mech creation rules, but there were some
> areas we weren't comfy with - for example, 'mechs can easily come out faster than
> small flyers with those rules, so we stuck with the '98 ones)
Let me see. My mech's torso's height is 4 "brix." The width is 6 "bumps." The
length is 8 "bumps."
Correct me if I am wrong:
4x6x8 = 192.
192 / 10 = 19.2
19.2, rounded would be 19.
So therefore, my medium mech costs 19 construction points for the chassis
alone? (No Pilot or Guns)
>
> shaun
This is the 100th post in this thread!! Yeeehaaww!
LegoMasterLuke
>
> LegoMasterLuke wrote:
>
> > In lugnet.loc.us.oh, David Eaton writes:
> > > In lugnet.loc.us.oh, Drew Lawrence writes:
> > > > Here is a loophole in the Vehicle system.... To get a treaded vehicle's cost,
> > > > you calculate out the area of the chassis, divide that by ten, and then add
> > > > the class number. My Small Mech has a chassis area of 16. Divided by 10, it
> > > > comes out to be 1.6, which, when rounded, is 2 CP. Then add the Class Number,
> > > > and the entire mech costs 4 cp. (No weapons or pilots added yet.. all in all,
> > > > however, it costs about 30 CP.)
> > >
> > > Actually, we used a different statistic for Mech's because of that "loophole"
> > > because it didn't seem very fair (hopefully Mike will forgive us, unless of
> > > course he was the one to suggest it... I don't know-- it wasn't my idea)... We
> > > essentailly modified that rule to measure the area of the largest plane
> > > contained within the "chassis". Hence, for a mech, you would measure the
> > > rectangular area in width times height, rather than width times length. But in
> > > general, the vehicle itself IS pretty cheap without weapons, turrets, etc.
> > > Although I will say, just for fun's sake, I calculated my AT-AT's value... that
> > > got expensive :) I think it came out to about 80pts for the chassis alone, and
> > > altogether something like 220 points (with the 3 pilots)!
> >
> >
> > Clarify that for me. Do you do < width x height > of the chassis, or of the
> > entire mech?
> >
> > And what is the height? What are we using as "1" height? A brik? a plate?
> >
> > LegoMasterLuke
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Message has 1 Reply: | | Re: CO BrikWars get together
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| (...) If you go by these guys' rules (which IMHO are pretty good rules), then you only multiply the larger two of the three dimensions: so for a 4brix x 6dots x 8dots, the larger two dimensions are 6 and 8, giving you a Size of 6x8=48. 48 makes your (...) (25 years ago, 14-Apr-00, to lugnet.loc.us.oh)
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Message is in Reply To:
| | Re: CO BrikWars get together
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| As for hieght, we used a brick (brik?) as being one unit. For 'mechs, we took the torso, and multiplied the larger two of the three dimensions. So a tall skinny 4x2x6 (width, depth, height) torso would cost as much as a short squat fatty 6x4x2. For (...) (25 years ago, 13-Apr-00, to lugnet.loc.us.oh)
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