Subject:
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Pneumatic T-cross math-rule
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Newsgroups:
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lugnet.technic
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Date:
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Tue, 21 Nov 2000 09:39:48 GMT
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Viewed:
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521 times
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Hi!
I'm onto this rather big pneumatics project where I have several
cylinders per switch and I found that if the numbers of cylinders used
is 'Y' and the number of T-crosses is 'X' then this is true (if you
use but one switch to control the whole thing):
Y2 - 2 = X
So if you need five cylinders on one switch you will need:
5 x 2 -2 = 8 T-crosses.
Or one cyinder gives:
1 x -2 = 0
But I guess it's easier to come to this conclusion when you need it
rather then remembering this rule. So why am I still sitting here
typing at corporate time?
Bah!
/Tobbe
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Message has 1 Reply:
 | | Re: Pneumatic T-cross math-rule
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| Basically, the number of T-pieces is one less than the number of cilinders. So with the same X and Y: X = Y - 1. That is, for the old ones that had only one tube going to them. For the new cilinders obviously you need twice as many: X = 2 x (Y - 1), (...) (24 years ago, 21-Nov-00, to lugnet.technic)
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