Subject:
|
Pneumatic T-cross math-rule
|
Newsgroups:
|
lugnet.technic
|
Date:
|
Tue, 21 Nov 2000 09:39:48 GMT
|
Viewed:
|
397 times
|
| |
|
|
Hi!
I'm onto this rather big pneumatics project where I have several
cylinders per switch and I found that if the numbers of cylinders used
is 'Y' and the number of T-crosses is 'X' then this is true (if you
use but one switch to control the whole thing):
Y2 - 2 = X
So if you need five cylinders on one switch you will need:
5 x 2 -2 = 8 T-crosses.
Or one cyinder gives:
1 x -2 = 0
But I guess it's easier to come to this conclusion when you need it
rather then remembering this rule. So why am I still sitting here
typing at corporate time?
Bah!
/Tobbe
|
|
Message has 1 Reply:
 | | Re: Pneumatic T-cross math-rule
|
| Basically, the number of T-pieces is one less than the number of cilinders. So with the same X and Y: X = Y - 1. That is, for the old ones that had only one tube going to them. For the new cilinders obviously you need twice as many: X = 2 x (Y - 1), (...) (24 years ago, 21-Nov-00, to lugnet.technic)
|
2 Messages in This Thread:
 
- Entire Thread on One Page:
- Nested:
All | Brief | Compact | Dots
Linear:
All | Brief | Compact
|
|
|
|
