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 | | Re: SSClagorpion
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| (...) Well Steve, it might and it might not. Given 18 bits of state (two bits/pistons per leg plus two extra), we could have a total of 256K possible combinations of leg positions. We only want about about 10 of them. If we start out the pistons in (...) (20 years ago, 16-Apr-04, to lugnet.technic)
| | | | | Re: SSClagorpion
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| (...) Yes, I'd rather see a solid, strong, slow robot over a fast robot that succeeds in tearing itself apart. :) (...) That's the throw of the switches, right? Not the throw of the cylinders on the legs. So the legs will "move" at the same speed, (...) (20 years ago, 15-Apr-04, to lugnet.technic)
| | | | | Re: SSClagorpion
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| In lugnet.technic, Kevin L. Clague wrote: <snip> (...) So using #1 axle connectors as the linkage, we get a reduced piston expansion, down to 86% of maximum. Using technic axle joiner perpendicular, we can reduce the range to 70% of maximum. I can't (...) (20 years ago, 15-Apr-04, to lugnet.technic)
| | | | | Re: 6293 rc receiver Auxiliary output possible?
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| thanks for checking Mark! that is more help than i expected. too bad it's not going to work. guess i'm going to have to buy another receiver from bricklink if i really want the extra output. bob (...) Bob Kojima ko@fial.com Fial Incorporated Telecom (...) (20 years ago, 15-Apr-04, to lugnet.technic, lugnet.robotics)
| | | | | Re: SSClagorpion
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| (...) Thinking about this more....... One of the reasons that makes this slow is the inherent piston friction which combined with pressure defines the rate of expansion and contraction. So the rate is not very negotiable. But using rate * time = (...) (20 years ago, 15-Apr-04, to lugnet.technic)
| | | | | Re: SSClagorpion
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| (...) <snip> (...) Well, I know of situations where LEGO has asked some people to recreate their MOCs for them. You know you have arrived if that happens. (...) Kevin (20 years ago, 15-Apr-04, to lugnet.technic)
| | | | | Re: SSClagorpion
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| (...) ... (...) With twice the pistons, the pressure is not as great, but the volume of air would be doubled, right? Using logic, not physics, I think once the pressure is built up (to 13 psi) the compressor may have to do less work to keep it (...) (20 years ago, 15-Apr-04, to lugnet.technic)
| | | | | Re: SSClagorpion
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| (...) Mark Riley was nice enought to point out the errors in my math. The area of the piston care is pi * r^2 = 0.2 Four times that is 0.8. So the minimal pressure needed is 10 pounds / 0.8 square inches or, 12.5 pounds per square inch. Still well (...) (20 years ago, 15-Apr-04, to lugnet.technic)
| | | | | Re: SSClagorpion
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| (...) Hmmmm.... interesting question. I don't know much pneumatic theory, but..... Pressure is in pounds per square inch. So if we know the area of the face of a piston, and we know the pressure we can determine how many pounds a single piston can (...) (20 years ago, 15-Apr-04, to lugnet.technic)
| | | | | carousel on MOCpages
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| I've finally finished the write-up of my carousel at (URL) to .spybotics because it's Spybot powered. (20 years ago, 15-Apr-04, to lugnet.robotics.spybotics, lugnet.technic, lugnet.town)
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