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Rossz Vámos-Wentworth <rossw@jps.net> wrote:
> In lugnet.robotics.rcx.legos, Luis Villa writes:
> > Actually, the kernel can hit 21-22K (depending on the compile-time
> > options.) My current legOS.srec sits at 21232 bytes. So, I'm going to do
> > the update.
>
> Isn't the actual size of the kernal about half the .srec size? That file
> contains ascii codes for for hex bytes, a pair of characters would be one
> byte.
Here's how to determine size given a .srec file:
1) Look at the last S1 line in the s-record file. An example from
firm0328.lgo:
S113E1606F...
2) Look at characters 4-8 (start counting with 0):
S113E1606F...
^^^^
This is the starting address for this S1 line.
3) Look also at the value in characters 2-3:
S113E1606F...
^^
This is the length of the line (in pairs of hex digits) not including
the S1 part but including a two-byte address and a one-byte checksum.
4) Add the two numbers and subtract 3:
E160 + 13 - 3 = E170
The resulting value is one more than the ending address of the firmware
file once loaded. It does not include the size of the bss data, which
also consumes space. (The bss data includes uninitialized global and
static-local variables.)
6) Since the starting address is 8000, you know the size of the file.
This one is E170 - 8000 = 6170h = 24944 bytes.
-Kekoa
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Message has 1 Reply:
 | | Re: Firmdl3 updated
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| (...) My legOS.srec file, which is compiled with all the default settings, is exactly 21000 bytes long. The calculated size is 8144. Which is sort of in the ballpark of half the file size (if we use a very big ballpark). The proper estimate is (...) (24 years ago, 20-Dec-00, to lugnet.robotics.rcx.legos)
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Message is in Reply To:
| | Re: Firmdl3 updated
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| (...) Isn't the actual size of the kernal about half the .srec size? That file contains ascii codes for for hex bytes, a pair of characters would be one byte. Rossz (24 years ago, 20-Dec-00, to lugnet.robotics.rcx.legos)
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