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Subject: 
Re: basic trigonometric functions on the handyboard..
Newsgroups: 
lugnet.robotics.handyboard
Date: 
Tue, 9 Mar 1999 21:40:15 GMT
Original-From: 
Scott Harris <SRHARRIS@PRINCETON.nospamEDU>
Viewed: 
3407 times
  
A Taylor series isn't the way to go: they converge far too slowly.

Here is a polynomial fit to arccos(x):

arccos(x) ~ =  1.5708 - 1.0927 x + 4.358 x^3 - 0.8340 x^5

It differs from the exact value of arccos(x) by no more that 0.08  radians (4.6
degrees) in the range [-1,1].

If you need more accuracy, just fit a polynomial with more terms to arccos.

-Scott



Thomas Heidel wrote:

> Hi,
> 
> The taylor for cos^-1 goes:
> 
> cos^-1(x) = Pi/2- (x + 1/2*x^3/3 + 1/2*3/4*x^5/5 + 1/2*3/4*5/6*x^7/7
> ...)
> 
>    (which in fact is simply Pi/2 - sin^-1)
> 
> The results are very good for small x. For x close to 1 you need many
> many
> elements of that series to be somehow accurate.
> 
> "SHETTI.NITIN.MANGESH" wrote:
> > 
> > Dear Berg,
> >         You can perhaps express cos^-1 in the forms of a Taylor series and
> > use that series for finding the approximate value. I have however not
> > tried it.
> >         There is no math function for inverse cosine.Refer to handy board
> > manual available el.www.mit.media.edu for details on IC.
> >                                                         Yours sincerely,
> >                                                             Nitin
> > 



Message is in Reply To:
  Re: basic trigonometric functions on the handyboard..
 
Hi, The taylor for cos^-1 goes: cos^-1(x) = Pi/2- (x + 1/2*x^3/3 + 1/2*3/4*x^5/5 + 1/2*3/4*5/6*x^7/7 ...) (which in fact is simply Pi/2 - sin^-1) The results are very good for small x. For x close to 1 you need many many elements of that series to (...) (28 years ago, 9-Mar-99, to lugnet.robotics.handyboard)

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