Subject:
|
Parts substitution
|
Newsgroups:
|
lugnet.robotics.handyboard
|
Date:
|
Thu, 10 Apr 1997 18:03:49 GMT
|
Original-From:
|
Bill Conroy <conroyw@acm.IHATESPAMorg>
|
Viewed:
|
1358 times
|
| |
|
|
I have a question on the replacement of the a specific resistor. On the
handyboard there is a 3.83K 1/8W resistor. I just received in the mail the
last pieces for the board and was shipped a 3.83K 1/4W resistor. Is the
wattage citical on this component.
Thanks,
William F. Conroy III conroyw@acm.org
Lt Col, USAF
|
|
Message has 2 Replies:
 | | Re: Parts substitution
|
| (...) I believe the wattage just tells you how much power the resistor can reasonable dissipate. Therefore using a transistor which can dissipate more power than what the design calls for is alright, but using one that dissipates less power is bad. (...) (27 years ago, 10-Apr-97, to lugnet.robotics.handyboard)
| | | Re: Parts substitution
|
| (...) In this case, no problem. The computation of power is simple... Watts = Volts X Amps and ohms law is... Volts = Resistance X Amps Using the traditional I = current (they say it comes from the French word for Intensity) R = Resistance E = (...) (27 years ago, 12-Apr-97, to lugnet.robotics.handyboard)
|
3 Messages in This Thread:
 
- Entire Thread on One Page:
- Nested:
All | Brief | Compact | Dots
Linear:
All | Brief | Compact
|
|
|
|
