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Subject: 
Re: Question?
Newsgroups: 
lugnet.robotics
Date: 
Mon, 4 Feb 2002 10:51:53 GMT
Viewed: 
823 times
  
lego-robotics@crynwr.com (T. Alexander Popiel) writes:

In message:  <200202031206_MC3-F079-6BD5@compuserve.com>
             PeterBalch <PeterBalch@compuserve.com> writes:
When set to use "active" sensors, the
inputs actually output power most of the time, switching briefly to
input mode (no power output) to take a reading.

What I don't understand is how this works if the sensor is connected
backwards.

Sure, a bridge rectifier will get the power sorted out but how does the
sensor send back a voltage in the right range? If say "light" is 8V and
"dark" is 0V then when the sensor is connected backwards, "light" will
be 0V and "dark" will be 8V.

My guess (having never looked at the schematics, or taken one apart)
is that when connected backwards, "dark" would be 0V and "light" would
be -8V.  Again, a simple bridge rectifier (this time in the RCX) would
get it sorted out.

No, there's no bridge in the RCX, just a pull-up to 5V (10kOhm IIRC).

If you look at the schematics
(say at http://philohome.free.fr/sensors/legorot.htm)
you see that there is another bridge rectifier in the sensor
between ground and the raw sensor output.
The ground half of the bridge is shared with the power supply bridge.

Jürgen

--
Jürgen Stuber <stuber@loria.fr>
http://www.loria.fr/~stuber/



Message is in Reply To:
  Re: Question?
 
(...) My guess (having never looked at the schematics, or taken one apart) is that when connected backwards, "dark" would be 0V and "light" would be -8V. Again, a simple bridge rectifier (this time in the RCX) would get it sorted out. It might be (...) (23 years ago, 4-Feb-02, to lugnet.robotics)

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