 | | Re: To all my friends!
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| (...) r = sqrt[(A^2/8D + D/2 - B^2/8D)^2 + B^2/4] where: A = chord 1 length B = chord 2 length D = perpindicular distance between A and B or you could search on cyclic quadrilateral and solve for r using that mess, simplifying for the quadrilateral (...) (23 years ago, 7-Nov-01, to lugnet.off-topic.geek)
| | | | | Re: To all my friends!
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| (...) Cool. Thank you to both of you--I can work with that formula. Dave! (23 years ago, 7-Nov-01, to lugnet.off-topic.geek)
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