Subject:
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Re: To all my friends!
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Newsgroups:
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lugnet.off-topic.geek
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Date:
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Wed, 7 Nov 2001 21:11:59 GMT
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Viewed:
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230 times
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In lugnet.off-topic.geek, Rob Doucette writes:
> In lugnet.off-topic.geek, Larry Pieniazek writes:
> > Pick any three and if oyu have a radius from 3 points thingie you're there.
>
> r = sqrt[(A^2/8D + D/2 - B^2/8D)^2 + B^2/4]
Cool. Thank you to both of you--I can work with that formula.
Dave!
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Message is in Reply To:
 | | Re: To all my friends!
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| (...) r = sqrt[(A^2/8D + D/2 - B^2/8D)^2 + B^2/4] where: A = chord 1 length B = chord 2 length D = perpindicular distance between A and B or you could search on cyclic quadrilateral and solve for r using that mess, simplifying for the quadrilateral (...) (23 years ago, 7-Nov-01, to lugnet.off-topic.geek)
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