Subject:
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Re: Math/Optics Problem
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Newsgroups:
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lugnet.off-topic.geek
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Date:
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Tue, 14 Aug 2001 08:28:25 GMT
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Viewed:
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99 times
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David:
> #1 Will the fisheye constant be consistant for the same camera?
No.
> #2 If not, will it at least be constant for the same zoom level?
No.
> #3 are there any other "missing pieces" to the formula?
Yes: Focus (I think).
> #4 what is the formula for figuring out the distance between the two objects?
dist. from camera = (fisheye const.)*(actual height)/(photo
height)
+ (small obscure camera dependent
constant)
Since you only ask about the relative distance, the "small
doesn't matter.
> #5 can I use that same formula to find out how far away from the *camera*
> the objects are?
Yes, but then you have to figure out the value of the "small
obscure camera dependent constant" .
Jacob
--
http://hugin.ldraw.org/Jacob/edb/digitale_nyheder
Om redaktørens opgave på internetnyhedstjenester.
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Message has 1 Reply:
 | | Re: Math/Optics Problem
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| (...) Hmm... So both the zoom and the focus affect the fisheye constant? How exactly does the focus change it? I guess I'm imagining the same actual image in and out of focus and not seeing actual change in the image's shapes & relative sizes... (...) (23 years ago, 14-Aug-01, to lugnet.off-topic.geek)
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Message is in Reply To:
| | Math/Optics Problem
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| So. Let's assume I have a photograph of Bob standing in front of his house. Knowing Bob the way I do, I know that Bob is 6 feet tall. And asking him later, I know that his house is 30 feet tall. Now I want to find out how far in front of his house (...) (23 years ago, 13-Aug-01, to lugnet.off-topic.geek)
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