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Mike,
Don't think it's going to work. 186,000 miles per second is almost
1,000,000,000 feet per second ... so if your receiver antennas are
12 inches apart the time difference of the received pulse will be
0.001 microseconds maximum ... way too short to measure with your
HandyBoard. You might give ultrasonics a try.
Good luck and have fun,
- Nick -
Michael Miranda wrote:
>
> Hi,
>
> I’m trying to get a robot to turn a face the owner
> using rf. I have one transmitter (that the owner will
> wear) and three receivers (set up in a triangle). We
> want to use the transmitter as a beacon. Then
> whichever receiver gets the signal first, that’s where
> the owner is and where we want to turn to. We can
> transmit to the receivers, but we can’t see which
> receiver is getting the signal first. I am trying to
> look at the falling edge of one pulse. In my program
> any receiver with a high signal will set its time
> variable to i (counter). And the last time its high
> corresponds to the falling edge. The problem seems to
> be the time of the loop is too slow and with in one
> loop all the signals change (at the same time). What
> I would like to do is speed up the loop, if that is
> possible. Can anyone help, is my thinking wrong?
> Here, is my code:
>
> float i, ta, tb, tc;
> void main(void)
> {
> ta=0.;
> tb=0.;
> tc=0.;
> i=0.;
> while (i<200.)
> {
> if (digital(11)==1)
> tb=i;
> if (digital(12)==1)
> ta=i;
> if (digital(13)==1)
> tc=i;
> i++;
> }
> printf("A%d B%d \rC%d\n",ta,tb,tc);
> }
>
> Mike
>
> __________________________________________________
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| Hi, I’m trying to get a robot to turn a face the owner using rf. I have one transmitter (that the owner will wear) and three receivers (set up in a triangle). We want to use the transmitter as a beacon. Then whichever receiver gets the signal first, (...) (25 years ago, 25-Nov-99, to lugnet.robotics.handyboard)
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