Hi,
I'm using for my base 12 v geared motors ,without load, each one drives
less than 100 mA, but when stalled, the current grow to 500 mA, wich is to
close to the 600 mA of L293 chips, i do not need more current, but i want to
protect the L293 from overloads, i have thinked in two solutions:
1- The simpler, put a 500 mA fuse between L293 and motor, but i dont know if
the fuse will be enough fast to protect the chip from a current peak.
2- what about to put a low value resistor, for example 1 ohm, in a series
connection with the motor and then use an analog input to measure the
voltage over the resistor, with a 100 mA (0.1 Volt over resistor) you will
read, if i'm not wrong, 250 in the analog(), and if the current up to 500mA
(0.5 Volt), you will read 230, with this data you can stop that motor to
protect the circuit.
What do you think?
José
Luis
PD: Sorry for my english
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