Subject:
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RE: High current motors
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Newsgroups:
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lugnet.robotics.handyboard
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Date:
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Mon, 15 Apr 1996 21:58:51 GMT
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Original-From:
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Chuck McManis <cmcmanis@netcom+nomorespam+.com>
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Viewed:
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2252 times
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Jeff is correct, after looking at the schematics for the motor driver my
circuit won't work. You will have to wire two sides of the motor driver
output to the 2907's with back to back diodes. I'll draw up a schematic
and post it. (In my original message I included the disclaimer that if
the the motor circuit was different than the miniboard circuit it wouldn't
work :-))
--Chuck
P.S. Fred, what do you use to put up those nice schematics?
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From: Jeff Keyzer[SMTP:jkeyzer@calweb.com]
Sent: Monday, April 15, 1996 7:33 AM
To: handyboard@media.mit.edu
Subject: Re: High current motors
> The motor connector has three pins they are actually Motor A, V+,
> Motor B. Normally they are all at V+ when the motor is "off" (the
> motor is simply monitoring the difference between Motor A and
> Motor B. When you "turn on" the motor either Motor A or Motor B
> (depending on direction) goes to ground potential, and the motor
> sees the voltage difference and runs.
On the handy board, this is different, isn't it? I didn't think
that the center pin was V+... In fact, isn't it not a connection at all?
> Now connect the emitter of one 2N2907 to the base of Q1, connect
> the emitter of the 2907 to a 180 ohm resistor and then connect
> the resistor to the base input of Q4. Do the same thing with
Isn't this supposed to read, "Now connect the COLLECTOR of one
2N2907 to the base of Q1, connect the EMITTER of the 2907 to a 180 ohm
resistor..." The way it's written just doesn't seem right.
Also, would it be possible to create a similar circuit using
non-darlington transistors, such as TIP 31 or 41's and their PNP
counterparts? They are much more readily available to me!
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