Subject:
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Somewhat C challenged.
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Newsgroups:
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lugnet.robotics.handyboard
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Date:
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Wed, 9 Apr 1997 22:51:19 GMT
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Original-From:
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victor w clark <{kvclark@juno.com}Spamless{}>
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Viewed:
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2398 times
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Please excuse my bitwise ignorance. Could someone explain this statement
to me.
if (4 & peek(0x1000))
what does peek(0x1000) return?
what is the 4 for ?
and what does the "&" compare?
thanks
victor
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Message has 1 Reply:
 | | Re: Somewhat C challenged.
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| Victor, The peek(0x1000) statement returns the byte at memory location 1000 (hex). In C, the '&' operator is a bitwise AND. So, what you are doing is ANDing 4 and the contents of 0x1000. What's really going on is you are interested in only bit 3 (...) (29 years ago, 10-Apr-97, to lugnet.robotics.handyboard)
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