Subject:
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Re: maze solving algorithm
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Newsgroups:
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lugnet.robotics
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Date:
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Sun, 8 Jun 2003 06:11:14 GMT
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Original-From:
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scott davis <rcx2man@hotmail.*nospam*com>
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Viewed:
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1325 times
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I'm back to working with NQC. I gave up on brickos. I think I have a
program that works, I just need to find some time to test it.
Thank you for your help.
Scott
----- Original Message -----
From: "Bluey" <Wolf_and_eagle@spamblock.yahoo.com>
To: <lego-robotics@crynwr.com>
Sent: Saturday, June 07, 2003 10:32 PM
Subject: Re: maze solving algorithm
> Ok, so did you get the idea about using the Binary system to identify the
> "cell"?
>
> Now, the next choice is what type of variable to use:
>
> You can use a small 16 bit variable for each "cell" which will take up 400
> bits=50 bytes. This was will conserve less memory, but it will make it easier
> for the robot to uncompress the data.
>
> Or, you can use a larger 32 bit variable to hold more info efficiently at 32 *
> 5=120 bits=20 bytes. This down side to this is, it will take more time to
> uncompress this, and it won't fit in a an array as well (since each variable
> would hold 5 of the "cells"; therefore needing an extra subroutine to extract
> the number.)
>
> I'm going to assume you chose the 16 bits per cell in an array option.
> Instead of wrapping our cell info into a 2 digit number, we can leave the raw
> binary info in the 5 digit variable. So, if our "cell" has no walls, we can just
> enter the number 00000 into the variable.
>
> Now for the next problem. The robot now has the ability to maneuver and map a
> 5x5 maze, but one thing that might not come to mind is the robot doesn't know
> where it is in the map when you start it out. For all it knows, when it enters
> the maze it could be in the middle of the bottom of the maze, or to the left or
> the right. Unless it know where the entrance is, it won't know where to place
> the map info it gathers. Make sense?
> The only two options I can think of are, 1. Have the entrance of the maze at a
> standard point in the maze (I.E. 3 "cells" from the right")
> (provided you are going to start the robot on the outside of the maze going in
> through an entrance), or 2. Have the robot construct a temporary map that is
> [(2*5)-1]x[(2*5)-1]=9x9 so that no matter where you put it to enter the maze, it
> start its mapping in the middle of the maze in it memory (I.E. coordinates 5,5),
> and will have space to fit.
>
> I don't know how you would create "temporary" variables in BrickOS unless you
> used disposable inline variables or classes (if those can be deconstructed at an
> earlier time). The problem is that the temporary map would need to be used as
> the main map until it figured out where it was......
>
> Or here is another idea, have the robot use a 5x5 memory map, and have it think
> it starts at (3,3). Then as it finds that a passage is actually the edge of the
> map, have it move the known map over one "cell" to accommodate the new info. In
> other-words, if you start the robot actually at the bottom middle of the maze,
> and the robot starts at (3,3) (in its map) and then it moves "up/north" 2
> "cells" (physically and in its map) then in its map, it will reach the top,
> middle "cell" of the "map in memory". Therefore, when it moves "north" one more
> space, it will be off the map, it could then see if there is an empty row at the
> bottom of the map. If there is an empty row, it could move all the cells down
> one space knowing that the map was oriented too far "north" compared to the
> actual maze.
> Do you understand? if not, I'll try explaining it again.
>
> I'm sorry if this is complicated or confusing. I'll try to elaborate on anything
> I didn't make clear.
>
> Timothy
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| | Re: maze solving algorithm
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| Ok, so did you get the idea about using the Binary system to identify the cell? Now, the next choice is what type of variable to use: You can use a small 16 bit variable for each cell which will take up 400 bits=50 bytes. This was will conserve (...) (21 years ago, 8-Jun-03, to lugnet.robotics)
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