Subject:
|
Re: Transit Time to Mars
|
Newsgroups:
|
lugnet.off-topic.geek
|
Date:
|
Thu, 16 Dec 1999 00:43:24 GMT
|
Viewed:
|
190 times
|
| |
|
|
On Wed, 15 Dec 1999 22:03:12 GMT, "Todd Lehman" <lehman@javanet.com>
wrote:
> Wow, cool, I get just over 1 day (~30 hours), which is probably short enough
> to ignore the fact that the source and target are both moving.
You too?
> But what about deceleration? :) Wouldn't a ship need to spend half of its
> time accelerating and half of its time decelerating?
Oops.
Jasper
|
|
Message has 1 Reply:
 | | Re: Transit Time to Mars
|
| Jasper Said: (...) Isn't that what the NASA guy said when they lost contact with the last martian probe? :) (Running, Ducking, and hiding under something very soild...like down a mine shaft...after all, after 30 hrs at 1 G acceleration, I don't want (...) (25 years ago, 16-Dec-99, to lugnet.off-topic.geek)
|
Message is in Reply To:
| | Re: Transit Time to Mars
|
| (...) Wow, cool, I get just over 1 day (~30 hours), which is probably short enough to ignore the fact that the source and target are both moving. I used s=½at² and solved for t. For s I used 5.8 x 10^10 m (36 x 10^6 miles) and for a I used 9.8 m/s². (...) (25 years ago, 15-Dec-99, to lugnet.off-topic.geek)
|
119 Messages in This Thread:
(Inline display suppressed due to large size. Click Dots below to view.)
- Entire Thread on One Page:
- Nested:
All | Brief | Compact | Dots
Linear:
All | Brief | Compact
This Message and its Replies on One Page:
- Nested:
All | Brief | Compact | Dots
Linear:
All | Brief | Compact
|
|
|
|
