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Subject: 
Re: Transit Time to Mars
Newsgroups: 
lugnet.off-topic.geek
Date: 
Thu, 16 Dec 1999 00:43:24 GMT
Viewed: 
223 times
  
On Wed, 15 Dec 1999 22:03:12 GMT, "Todd Lehman" <lehman@javanet.com>
wrote:

Wow, cool, I get just over 1 day (~30 hours), which is probably short enough
to ignore the fact that the source and target are both moving.

You too?

But what about deceleration?  :)  Wouldn't a ship need to spend half of its
time accelerating and half of its time decelerating?

Oops.

Jasper



Message has 1 Reply:
  Re: Transit Time to Mars
 
Jasper Said: (...) Isn't that what the NASA guy said when they lost contact with the last martian probe? :) (Running, Ducking, and hiding under something very soild...like down a mine shaft...after all, after 30 hrs at 1 G acceleration, I don't want (...) (25 years ago, 16-Dec-99, to lugnet.off-topic.geek)

Message is in Reply To:
  Re: Transit Time to Mars
 
(...) Wow, cool, I get just over 1 day (~30 hours), which is probably short enough to ignore the fact that the source and target are both moving. I used s=½at² and solved for t. For s I used 5.8 x 10^10 m (36 x 10^6 miles) and for a I used 9.8 m/s². (...) (25 years ago, 15-Dec-99, to lugnet.off-topic.geek)

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