 | | Re: Transit Time to Mars
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| (...) Wow, cool, I get just over 1 day (~30 hours), which is probably short enough to ignore the fact that the source and target are both moving. I used s=½at² and solved for t. For s I used 5.8 x 10^10 m (36 x 10^6 miles) and for a I used 9.8 m/s². (...) (25 years ago, 15-Dec-99, to lugnet.off-topic.geek)
| | | | | Re: Transit Time to Mars
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| (...) You too? (...) Oops. Jasper (25 years ago, 16-Dec-99, to lugnet.off-topic.geek)
| | | | | Re: Transit Time to Mars
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| Jasper Said: (...) Isn't that what the NASA guy said when they lost contact with the last martian probe? :) (Running, Ducking, and hiding under something very soild...like down a mine shaft...after all, after 30 hrs at 1 G acceleration, I don't want (...) (25 years ago, 16-Dec-99, to lugnet.off-topic.geek)
| | | | | Re: Transit Time to Mars
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| (...) I refer you to: (URL) (25 years ago, 16-Dec-99, to lugnet.off-topic.geek)
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