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Subject: 
Re: Dumb question, in all probability
Newsgroups: 
lugnet.off-topic.geek
Date: 
Wed, 24 Mar 2004 18:26:54 GMT
Viewed: 
544 times
  
In lugnet.off-topic.geek, Dave Schuler wrote:
Assuming that a pack of the new Black&White M&M's has exactly 50 of each color,
what are the odds that the first five candies drawn from the package will be of
the same color?

Assuming a perfect draw (50% chance of either color if there are 100 candies
present with 50 each) and that the draw is without replacement..

let's work the white case first, that is, what is the probability of WWWWW ?

50/100*49/99*48/98*47/97*46/96  (draw is without replacement)

or 254251200 /  9034502400

or 0.028142247

The probability of BBBBB is exactly the same, therefore you can add the two
outcomes

0.028142247 + 0.028142247

or 0.056284494

or about 5.5%

That's my answer. Hope it's right!

Note that if the draw is WITH replacement the answer is different, it's 5*
(50/100) * 2 (to account for each possible outcome) or .0625



Message has 1 Reply:
  Re: Dumb question, in all probability
 
(...) I was on the right track until this step. Why are the BBBBB and WWWWW results added together? (...) Thanks for playing, in any case. Dave! (21 years ago, 24-Mar-04, to lugnet.off-topic.geek)

Message is in Reply To:
  Dumb question, in all probability
 
Assuming that a pack of the new Black&White M&M's has exactly 50 of each color, what are the odds that the first five candies drawn from the package will be of the same color? (21 years ago, 24-Mar-04, to lugnet.off-topic.geek)

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