Subject:
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Re: On a scale of 0 to 10?
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Newsgroups:
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lugnet.off-topic.geek
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Date:
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Wed, 26 Mar 2003 19:55:42 GMT
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Viewed:
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369 times
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Hi all.
The reason the equation is unsolvable is because B is an unneeded constant.
Why?
A*e^(q+B)=A*(e^q)*(e^B)
It is impossible to distinquish between A & e^B.
What you need to solve is an equation of the form
s=A*exp(B*q) + C
This is the form of an equation to solve numerous differential equations in
engineering, such as RC circuits and heat transfers.
John
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Message has 1 Reply:
 | | Re: On a scale of 0 to 10?
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| (...) aHA! Much oblige! I now get (approx): s = 5.39 * e^(2.625q) - 0.39 Whew. Of course, now here's a totally different question. In order to get that point, I cheated. I couldn't solve: e^(B/4) + e^(-B) = 2 using algebra, but using other means, I (...) (22 years ago, 26-Mar-03, to lugnet.off-topic.geek)
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Message is in Reply To:
| | Re: On a scale of 0 to 10?
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| (...) Oh yeah! (...) Oh... yeah. (...) Hm. Double checked the math-- it appears solid [1], which would mean that there's no viable solution for: s = Ae^(q + B) + C for coordinates (-1,0), (0,5), (0.25,10). Darn. Hm. I guess that also means that any (...) (22 years ago, 26-Mar-03, to lugnet.off-topic.geek)
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